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Tutor profile: Jasmeet Kaur S.

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Jasmeet Kaur S.
Currently a Business Owner - Was a Tutor for 4 years
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Questions

Subject: Pre-Algebra

TutorMe
Question:

Simplify the left side: -2 (y + 2) = 2 -y

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Jasmeet Kaur S.
Answer:

Step 1: Apply the distributive property -2 (y + 2) = 2 -y -2y - 4 = 2-y Step 2: Move all terms containing y to the left side of the equation -2y - 4 + y = 2 -combine like terms -y - 4 = 2 Step 3: Move all constants to the right side of the equation -y = 6 Answer: y = -6

Subject: Microeconomics

TutorMe
Question:

Here are two equations for the demand and supply curve: Demand curve: Qd = 3300 - 2P Supply curve: Qs = 500 + 8P Compute the equilibrium price value

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Jasmeet Kaur S.
Answer:

Remember that equilibrium is the point where quantity demanded equals the quantity supplied. To find equilibrium, set the demand and supply curve equal to each other and solve for P. Step 1: Combine like terms by adding 2P to both sides 3300 - 2P = 500 + 8P + 2P . + 2P 3300 = 500 + 10P Step 2: Subtract 500 to combine like terms 3300 - 500 = 500 + 10P - 500 Step 3: Divide 10 from both sides to isolate P. 2800 = 10P 2800/10 = 10P/10 P = 280

Subject: Algebra

TutorMe
Question:

Find x: 2(x+5) - 7 = 3(x-2)

Inactive
Jasmeet Kaur S.
Answer:

2(x+5) - 7 = 3(x-2) -use the distributive property 2x + 10 - 7 = 3x - 6 -combine like terms 2x + 3 = 3x - 6 -subtract 3x from both sides to combine like terms 2x + 3 - 3x = 3x - 6 - 3x -combine like terms -x + 3 = -6 -subtract 3 from both sides to combine like terms -x + 3 - 3 = -6 - 3 -x = -9 -divide out -1 from both sides x = 9

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