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# Tutor profile: Jenny C.

Inactive
Jenny C.
Tutor for 3 years
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## Questions

### Subject:Mandarin

TutorMe
Question:

If you have just meet a friend from China and you want to keep in touch with him/her in the future, what should you do?

Inactive
Jenny C.

You can ask him/her if you can add him/her on WeChat (a popular social media in China) by asking, "我wo可ke以yi加jia你ni微wei信xin吗ma?"

### Subject:Pre-Calculus

TutorMe
Question:

find the mi/max value for f(x)=x^2-4x

Inactive
Jenny C.

when x=0 or x=4, f(x)=0, since the graph is symmetric, when x=2, f(x) reaches its min value. Thus, f(x)min=2^2-4*2=4-8=-4

### Subject:Basic Math

TutorMe
Question:

X^2-4x=0, find x

Inactive
Jenny C.

x^2-4x=x(x-4)=0, x=0 or x=4

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