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Tutor profile: Naomi S.

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Naomi S.
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Questions

Subject: Hebrew

TutorMe
Question:

What skills are you able to assist with in Hebrew?

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Naomi S.
Answer:

I am able to assist with various aspects of language acquisition including, letters, reading, vocabulary, conjugation, conversation, prayer. I do not consider myself completely fluent, but conversational.

Subject: Education

TutorMe
Question:

How would you handle a student who is unwilling to complete assignments?

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Naomi S.
Answer:

First, I would sit down with the student and ask him or her why they are not completing the work. It is easy to assume that the student just doesn't want to complete the work. One may find that the student is having trouble understanding the work and would rather be seen as the student who doesn't do work than the "dumb student." If this is the case, I would work with the student and his family to try to come up with a way for him or her to get extra help and would recommend tutors and websites for assistance. I would also begin to implement interventions so that if I later feel that the student may be in need of extra services, he or she would be eligible to be tested for them.

Subject: Algebra

TutorMe
Question:

There are two numbers. Their sum is 11 and their difference is 3. What are the two numbers?

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Naomi S.
Answer:

As we have two numbers that we do not know that value of, we are going to designate them each with a variable- x and y. We know that when we add them together, we get 11. Therefore we can write, x+y=11 Likewise, we know that when we subtract one from the other, we get 3. Therefore, we can write x-y=3 The easiest way to solve this problem is to solve for one variable at a time. I am going to start with x, but it does not matter what variable you choose. Based on the rules of mathematics, we know that if x+y=11, then x=11-y. You might be thinking, how does this help us? That doesn't give us a number. What we do with this? What you want to do is take x=11-y and plug is into the second equation of x-y=3. It would look as follows. x-y=3 (11-y)-y=3 11-2y=3 -2y=3-11 -2y=-8 /(-2) /(-2) y=4 Now that we know that y=4, we can plug that into either of the original equations. x+y=11 x+4=11 x=11-4 x=7 OR x-y=3 x-4=3 x=3+4 x=7 And Voila! You have solved for the two unknown numbers!

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