Enable contrast version

# Tutor profile: Anirban D.

Inactive
Anirban D.
Your friendly maths tutor, engineer in Munich
Tutor Satisfaction Guarantee

## Questions

### Subject:Trigonometry

TutorMe
Question:

Solve the trigonometric equation for x: tan3x=1/tan2x.

Inactive
Anirban D.

Since 1/tanA = tan (π/2 − A), we can write the above equation as tan3x = tan(π/2 − 2x), 3x = (π/2 − 2x) + Kπ, since if tanA = tanB, then A = B + Kπ, where K= some integer 3x − (π/2 − 2x) = Kπ, 5x − π/2 = κπ, 5x = Kπ + π/2, x = Kπ/5 + π/10

### Subject:Geometry

TutorMe
Question:

A rectangular swimming pool has a length of 30 meters, a width of 10 meters, and an average depth of 2 meters. If a hose can fill the pool at a rate of 0.5 cubic meters per minute, how many hours will it take the hose to fill the pool?

Inactive
Anirban D.

Since the swimming pool is rectangular, we can find its volume as the length, width and height (depth) are already given. So, volume = length X width X height = 30 X 10 X 2 = 600 cubic meters Rate of filling the pool by the hose = 0.5 cubic meters per minute. Therefore, hours taken by the hose to fill the pool =(600 cubic meter)/ (0.5 cubic meters per minute) =600/0.5 minutes =6000/5 minutes =1200 minutes =1200/60 hours =20 hours

### Subject:Algebra

TutorMe
Question:

Two people are 14 miles apart and begin walking towards each other. Person A walks 3 miles per hour and Person B walks 4 miles per hour. How long will it take them to reach each other?

Inactive
Anirban D.

Total distance to be covered by walking= 14 miles Distance covered by A = lets say, d miles Then, distance covered by B = 14 - d miles. Both use the same amount of time to meet each other and lets refer that time as t hours. By the equation, speed X time = distance, we get: since speed of A is 3 miles/hour, equation for A: 3t = d...............................(1) Similarly, equation for B: 4t = 14 - d........................(2) Substituting the value of d from (1) to (2), 4t = 14 - 3t 4t + 3t = 14 7t = 14 t= 2 Therefore, it will take 2 hours for A and B to reach each other.

## Contact tutor

Send a message explaining your
needs and Anirban will reply soon.
Contact Anirban

Start Lesson

## FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.
BEST IN CLASS SINCE 2015
TutorMe homepage