TutorMe homepage

SIGN IN

Start Free Trial

Alok M.

I am an experienced online tutor. I have been associated with online tutoring for more than five years.

Tutor Satisfaction Guarantee

Pre-Calculus

TutorMe

Question:

Given f(x)=(x+2)/(x-3) find f^-1(x).

Alok M.

Answer:

To find f^-1(x) we need to set f(x)=y , y =(x+2)/(x-3). then we flip x and y . we have x =(y+2)/(y-3). multiplying both sides by x(y-3)=y+2. xy -3x=y+2. on simplifying we have y(x-1)=3x+2.The required inverse y =(3x+2)/(x-1)

Calculus

TutorMe

Question:

What is the slope of the tangent line of the function f(x)=2x^3−4x^2−3x at x=2x=2?

Alok M.

Answer:

To find the slope first we need to find the derivative f'(x)=6x^2-8x-3 . Now we need to plug x=2 wherever we see x in f'(x). f'(2)=6(2)^2-8(2)-3=24-16-3=24-19=5.Hence the required slope is 5.

Algebra

TutorMe

Question:

The admission fee at a small fair is $1.50 for children and $4.00 for adults. On a certain day, 2200 people enter the fair and $5050 is collected. How many children and how many adults attended?

Alok M.

Answer:

I would have set this up by picking a variable for one of the groups (say, "c" for "children") and then use "(total) less (what I've already accounted for)" (in this case, "2200 – c") for the other group. Using a system of equations, however, allows me to use two different variables for the two different unknowns. number of adults: a number of children: c With these variables, I can create equations for the totals they've given me: total number: a + c = 2200 total income: 4a + 1.5c = 5050 Now I can solve the system for the number of adults and the number of children. I will solve the first equation for one of the variables, and then substitute the result into the other equation: a = 2200 – c 4(2200 – c) + 1.5c = 5050 8800 – 4c + 1.5c = 5050 8800 – 2.5c = 5050 –2.5c = –3750 c = 1500 Now I can back-solve for the value of the other variable: a = 2200 – (1500) = 700 1500 children and 700 adults.

Send a message explaining your

needs and Alok will reply soon.

needs and Alok will reply soon.

Contact Alok

Ready now? Request a lesson.

Start Session

FAQs

What is a lesson?

A lesson is virtual lesson space on our platform where you and a tutor can communicate.
You'll have the option to communicate using video/audio as well as text chat.
You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.

How do I begin a lesson?

If the tutor is currently online, you can click the "Start Session" button above.
If they are offline, you can always send them a message to schedule a lesson.

Who are TutorMe tutors?

Many of our tutors are current college students or recent graduates of top-tier universities
like MIT, Harvard and USC.
TutorMe has thousands of top-quality tutors available to work with you.

Made in California

© 2019 TutorMe.com, Inc.