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# Tutor profile: Irfaan K.

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Irfaan K.
Incoming Software Development Engineer at Amazon | Computer Science & Applied Math majors at Vanderbilt University
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## Questions

### Subject:Computer Science (General)

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Question:

Suppose you have an array of integers \$\$arr\$\$ with an arbitrary length. Write a method/function called \$\$average\$\$ which takes one parameter (\$\$arr\$\$) which returns the mean of all the elements in \$\$arr\$\$ as a double. You may complete this challenge in any programming language of your choice.

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Irfaan K.

We can solve this problem using a for-loop. Here's an example solution in Java: private static double average(int[] arr) { int sum = 0; for (int elem : arr) { sum += elem; } return (double) sum / arr.length }

### Subject:ACT

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Question:

Suppose you have a triangle \$\$\Delta ABC\$\$. If \$\$\angle A\$\$ is \$\$90°\$\$ and \$\$\angle B\$\$ is \$\$56°\$\$, which of the following statements can we make about \$\$\angle C\$\$? \$\$A)\$\$ \$\$\angle C\$\$ is \$\$90°\$\$ \$\$B)\$\$ \$\$\angle C\$\$ is \$\$34°\$\$ \$\$C)\$\$ \$\$\angle C\$\$ is larger than \$\$56°\$\$ \$\$D)\$\$ None of the above

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Irfaan K.

Fundamentally, we must recall that the sum of all angles of any triangle is \$\$180°\$\$. Provided we know this, we can determine that \$\$\angle A + \angle B + \angle C = 180°\$\$. We know that \$\$\angle A\$\$ is \$\$90°\$\$ and \$\$\angle B\$\$ is \$\$56°\$\$, so we can solve for \$\$\angle C\$\$ via substitution: \$\$90° + 56° + \angle C = 180°\$\$ \$\$146° + \angle C = 180°\$\$ \$\$\angle C = 180° - 146°\$\$ \$\$\angle C = 34°\$\$ Therefore, option \$\$B\$\$ is the correct choice.

### Subject:Algebra

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Question:

Consider \$\$f(x) = x^2 + 4x - 21\$\$. Determine where \$\$f(x)\$\$ intersects the x-axis.

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Irfaan K.

We begin by factoring \$\$f(x) = x^2 + 4x - 21\$\$ - doing so will help us determine the roots of \$\$f(x)\$\$ and, subsequently, where the graph intersects the x-axis. We factor \$\$f(x)\$\$ and obtain \$\$f(x) = (x+7)(x-4)\$\$. Now, we take each of these roots and set them equal to \$\$0\$\$ to determine our points of intersection along the x-axis. Solving \$\$(x+7) = 0\$\$ yields \$\$x=-7\$\$. Solving \$\$(x-4) = 0\$\$ yields \$\$x=4\$\$. Therefore, \$\$f(x)\$\$ intersects the x-axis at two points: \$\$x=-7\$\$ and \$\$x=4\$\$.

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