Using the Unit circle find the value of the trigonometric functions at the radian degree measure of 60 degrees
The value of sin(60)=sqrt(3)/2, cos(60)=1/2, tan(60)=sqrt(3)
What is the formula to find a midpoint of a segment? And given the endpoints of the line segment PQ as P(1,5) and Q(7,2), what is the midpoint of the line segment PQ?
The formula for the midpoint of a segment is M=(((x_1+x_2)/2),((y_1+y_2)/2). Now using this formula we plug in the points P and Q and find the midpoint. M=((1+5)/2,(5+2)/2). M=(3,3.5)
Take the derivative of f(x)=3(x^2)+2xe^x using the derivative rules.
The derivative of f(x)=3(x^2)+2xe^x is: f'(x)=6x+2x(e^x)+2(e^x) This was obtained using the product rule.