# Tutor profile: Isabel R.

## Questions

### Subject: Study Skills

Sometimes I do poorly on tests even though I understand the material! What should I do?

It sounds like you might want to develop some test-taking strategies! Sometimes, no matter how well you grasp the content, the stress of taking an exam can make you forget the answers or run out of time. If that's the case, I recommend trying to simulate a test-taking environment at home before your test! Someone, maybe a parent, can time you while you answer a series of practice questions so you can prepare for what it will be like on the day of the actual day of the test. This can help you get used to the time limit and the pressure that may be holding you back.

### Subject: College Admissions

How do I create a balanced college list?

When thinking of where to apply to college, it is crucial to develop a balanced list. This means having a combination of safety, target, and reach schools. A safety school is one that you will almost certainly be accepted to because your GPA and test scores are above the average. A target school is a great academic fit for you because your GPA and test scores are very close to the average. For reach schools, your GPA and test scores may be below the average, but you still have a shot of being accepted. The bulk of the schools that you apply to should be target schools, as these are likely the best fit, but is important to apply to schools from all categories. This will give you a range of options when you ultimately decide where to attend!

### Subject: Algebra

The following equation represents the height h, in feet, of a ball t seconds after it is dropped from an elevated platform that is 50 feet high. After how many seconds will the ball hit the floor? h = -7t^2 + 63

In this word problem, we are dealing with two variables: height (h) and time (t). The question is asking us to find the time, t, when the ball hits the ground. So we first have to ask ourselves, what is h? When the ball hits the ground, then it will be 0 feet off the ground. In other words, h = 0. So, we plug h into our equation and solve for t, and we do this by isolating t! By the order of operations, we will first subtract 63 from both sides, leaving us with -63 = -7t^2. Next, we will divide by -7 on both sides, leaving us with 9 = t^2. Lastly, we will take the square root on both sides to get t = 3 or -3. However, we cannot have negative time, so we are left with t = 3 seconds!

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