Enable contrast version

# Tutor profile: Umair C.

Inactive
Umair C.
Software Test Engineer at Comcast
Tutor Satisfaction Guarantee

## Questions

### Subject:Pre-Calculus

TutorMe
Question:

Solve for x in the following equation: (1/x-3)+(1/x+3) = 4/(x^2-9)

Inactive
Umair C.

x = 2

### Subject:Basic Math

TutorMe
Question:

If the perimeter of a rectangular house is 25 yards, and the length is 22 feet. What is the width?

Inactive
Umair C.

First, the perimeter measurement may be converted to feet. Multiplying 25 yards by 3 gives an equivalent measurement of 75 feet. Thus, the following equation may be written: 75 = 2(22) + 2w, which simplifies to 75 = 44 + 2w, where w = 15.5. The width of the house is 15.5 ft.

### Subject:Algebra

TutorMe
Question:

Evaluate: 30 - 15÷3×2

Inactive
Umair C.

According to order of operations, 15÷3×2 (division and multiplication) is done first from left to right 15÷3×2 = 5 × 2 = 10 Hence 30 - 15÷3×2 = 30 - 10 = 20

## Contact tutor

Send a message explaining your
needs and Umair will reply soon.
Contact Umair