# Tutor profile: Umair C.

Inactive

Umair C.

Software Test Engineer at Comcast

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## Questions

### Subject: Pre-Calculus

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Question:

Solve for x in the following equation: (1/x-3)+(1/x+3) = 4/(x^2-9)

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Umair C.

Answer:

x = 2

### Subject: Basic Math

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Question:

If the perimeter of a rectangular house is 25 yards, and the length is 22 feet. What is the width?

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Umair C.

Answer:

First, the perimeter measurement may be converted to feet. Multiplying 25 yards by 3 gives an equivalent measurement of 75 feet. Thus, the following equation may be written: 75 = 2(22) + 2w, which simplifies to 75 = 44 + 2w, where w = 15.5. The width of the house is 15.5 ft.

### Subject: Algebra

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Question:

Evaluate: 30 - 15÷3×2

Inactive

Umair C.

Answer:

According to order of operations, 15÷3×2 (division and multiplication) is done first from left to right 15÷3×2 = 5 × 2 = 10 Hence 30 - 15÷3×2 = 30 - 10 = 20

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