# Tutor profile: Megan A.

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Megan A.

Private tutor during high school

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## Questions

### Subject: Basic Math

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Question:

4(4X) + 2(X) = 72 Solve for X.

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Megan A.

Answer:

Simplify. 16(X) + 2(X) = 72 Add common factors. 18(X) = 72 Divide both side of the equation by 18. X = 4

### Subject: Basic Chemistry

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Question:

How many mL of a 2.50 M NaOH solution are required to make 525 mL of a 0.150 M NaOh solution?

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Megan A.

Answer:

M1 x V1 = M2 x V2 (Volume in L) 1000 mL = 1 L 525 mL = .525 L M1 = 2.5 V1 = Unknown M2 = 0.150 V2 = .525 L (2.5 M)(X) = (.15)(.525) solve for X X = 0.0315

### Subject: Algebra

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Question:

Solve for x. X/4 + 2 = 7/2 - 2X

Inactive

Megan A.

Answer:

The lowest common multiple of 4 is 2 and 4. 4 x (X/4 + 2) = 4 x (7.5 - 2X) : Multiply both side by 4 X + 8 = 30 - 8X X + 8 + 8X = 30 - 8X + 8X : Add 8X to each side of the equation 9X + 8 = 30 9X + 8 - 8 = 30 - 8 : Subtract 8 from each side 9X = 20 Divide each side by 9 X = 2.33

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