Subjects
PRICING
COURSES
SIGN IN
Start Free Trial
Megan A.
Private tutor during high school
Tutor Satisfaction Guarantee
Basic Math
TutorMe
Question:

4(4X) + 2(X) = 72 Solve for X.

Megan A.
Answer:

Simplify. 16(X) + 2(X) = 72 Add common factors. 18(X) = 72 Divide both side of the equation by 18. X = 4

Basic Chemistry
TutorMe
Question:

How many mL of a 2.50 M NaOH solution are required to make 525 mL of a 0.150 M NaOh solution?

Megan A.
Answer:

M1 x V1 = M2 x V2 (Volume in L) 1000 mL = 1 L 525 mL = .525 L M1 = 2.5 V1 = Unknown M2 = 0.150 V2 = .525 L (2.5 M)(X) = (.15)(.525) solve for X X = 0.0315

Algebra
TutorMe
Question:

Solve for x. X/4 + 2 = 7/2 - 2X

Megan A.
Answer:

The lowest common multiple of 4 is 2 and 4. 4 x (X/4 + 2) = 4 x (7.5 - 2X) : Multiply both side by 4 X + 8 = 30 - 8X X + 8 + 8X = 30 - 8X + 8X : Add 8X to each side of the equation 9X + 8 = 30 9X + 8 - 8 = 30 - 8 : Subtract 8 from each side 9X = 20 Divide each side by 9 X = 2.33

Send a message explaining your
needs and Megan will reply soon.
Contact Megan
Ready now? Request a lesson.
Start Session
FAQs
What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Session" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.