Subjects
PRICING
COURSES
SIGN IN
Start Free Trial
Jamie S.
Math Teacher (for 10 years), Math tutor (for 1 year)
Tutor Satisfaction Guarantee
Algebra
TutorMe
Question:

Cell phone carrier A offers a plan for $40/month plus $0.25/MB of data used. Cell Phone carrier B offers a plan for $30/month plus $0.30/MB used. How can y/ou use a system of equations to figure out which cell phone plan is the best deal? When is Plan A a better deal? When is Plan B a better deal?

Jamie S.
Answer:

You can use a system of equations by writing an algebraic equation to represent each carrier's plan. Plan A: C=40+0.25m ; Plan B: C=30+0.3m ; where C = monthly cost and m = MB of data used. Then you can solve the system with a graph or by setting the equations equal to each other (substitution), to determine how many MB you would need to use so that the plans would have an equal monthly cost. Then you would need to determine if you are going to use more or less MB than that to see which plan will work best for you. If you use more than 200 MB of data each month, then Plan A will be a better deal for you. If you use less than 200 MB of data each month then Plan B will be a better deal.

Basic Math
TutorMe
Question:

Use factoring to solve this quadratic equation. x^2 + 2x - 10 = 5

Jamie S.
Answer:

Start by getting the equation to equal 0. To do this you would subtract 5 from each side. x^2 + 2x - 10 - 5 = 5 - 5 x^2 +2x -15 = 0 Now factor the equation. You are looking for two numbers that add to 2 and multiply to -15. You know you are looking for one positive and one negative number since the multiply to a negative. The two numbers are 5 and -3. You will use these two numbers in your two binomials that you factor. (x+5) (x-3) = 0 Since you have two factors being multiplied to 0, you know that one of them has to equal 0. Set each factor to equal 0 and solve each new equation. x+5=0 and x-3=0 x= -5 and x=3 These are your two solutions to the original quadratic equation. To check your answers, plug each number in (separately) the original equation to see that it makes the equation true. x^2 + 2x - 10 = 5 (-5)^2 + 2(-5) - 10 = 5 25 + (-10) - 10 = 5 15 - 10 = 5 5 = 5 (true) x^2 + 2x - 10 = 5 (3)^2 + 2(3) - 10 = 5 9 + 6 - 10 = 5 15 - 10 = 5 5 = 5 (true)

Pre-Algebra
TutorMe
Question:

Without graphing or solving, how can you determine whether the following system of equations will have one solution, no solutions, or infinitely many solutions? y = -3x + 4 6x + 2y = 8

Jamie S.
Answer:

To determine the number of solutions with out graphing or solving you need to determine if these two linear equations are intersecting lines, parallel lines, or the same line. If they are intersecting lines, they will have two different slopes. If they are parallel lines they will have the same slope, but different y intercepts. If they are the same line they will have the same slope and the same y intercept. To find the slope and y intercept it is easiest to put each equation in slope-intercept form (y=mx + b; where m is the slope and b is the y intercept.) The first equation is already in this form so we just need to change the second equation by solving for y. 6x + 2y = 8 6x -6x +2y = 8 - 6x (subtract 6x from bothh sides) 2y = -6x + 8 (Simplify) 2y/2 = -6x/2 + 8/2 (divide each term by 2, to isolate y) y = -3x + 4 Since the two equations have the same slope and the same y intercept, there will be infinitely many solutions to this system of equations.

Send a message explaining your
needs and Jamie will reply soon.
Contact Jamie
Ready now? Request a lesson.
Start Session
FAQs
What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Session" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.