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# Tutor profile: Jessah Marie B.

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Jessah Marie B.
Full-time Tutor for 5 years
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## Questions

### Subject:Trigonometry

TutorMe
Question:

if sin A = √3/2 and cos A = -1/2, find sec A, csc A, cot A and tan A.

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Jessah Marie B.

sec A = $$\frac{1}{cos A}$$ = $$\frac{1}{-1/2}$$ = $$-2$$ csc A = $$\frac{1}{sin A}$$ = $$\frac{1}{√3/2}$$ = $$\frac {2}{√3}$$ = $$\frac {2√3}{3}$$ tan A = $$\frac{sin A}{cos A}$$ = $$\frac{√3/2}{-1/2}$$ = $$-√3$$ cot A = $$\frac{1}{tan A}$$ = $$\frac{1}{-√3}$$ = $$\frac{-√3}{3}$$

### Subject:Basic Math

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Question:

Cynthia can type 45 words per minute. How many words can she type in 5 hours?

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Jessah Marie B.

Given : rate = 45 words per minute time = 5 hours First step is to convert 5 hours to minutes. 1 hour = 60 minutes $$\frac{60 minutes}{1 hour}$$ x $$5 hours$$ = 300 minutes Number of words = rate x time = 45 words per minute x 300 minutes = 13,500 words

### Subject:Statistics

TutorMe
Question:

Determine the sample size to be considered for as research work that will involve population of 52, 480 students if the desired margin of error is 7%.

Inactive
Jessah Marie B.

To determine the sample we will apply the Slovin's formula : $$\frac{N}{1+Ne^2}$$ wherein N is the population and e is the margin of error. *Note that margin of error must be in decimal form. In the question N = 52, 480 and e = 0.07 Substituting the value in our formula : $$\frac{52,480}{1+52,480(0.07)^2}$$ Answer : 203. 29 since we are looking for the sample size we need to round it up so our final answer is 204.

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