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Tutor profile: Jessah Marie B.

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Jessah Marie B.
Full-time Tutor for 5 years
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Questions

Subject: Trigonometry

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Question:

if sin A = √3/2 and cos A = -1/2, find sec A, csc A, cot A and tan A.

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Jessah Marie B.
Answer:

sec A = $$ \frac{1}{cos A} $$ = $$ \frac{1}{-1/2} $$ = $$ -2 $$ csc A = $$ \frac{1}{sin A} $$ = $$ \frac{1}{√3/2} $$ = $$ \frac {2}{√3} $$ = $$ \frac {2√3}{3} $$ tan A = $$ \frac{sin A}{cos A} $$ = $$ \frac{√3/2}{-1/2} $$ = $$ -√3 $$ cot A = $$ \frac{1}{tan A} $$ = $$ \frac{1}{-√3} $$ = $$ \frac{-√3}{3}$$

Subject: Basic Math

TutorMe
Question:

Cynthia can type 45 words per minute. How many words can she type in 5 hours?

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Jessah Marie B.
Answer:

Given : rate = 45 words per minute time = 5 hours First step is to convert 5 hours to minutes. 1 hour = 60 minutes $$ \frac{60 minutes}{1 hour} $$ x $$ 5 hours $$ = 300 minutes Number of words = rate x time = 45 words per minute x 300 minutes = 13,500 words

Subject: Statistics

TutorMe
Question:

Determine the sample size to be considered for as research work that will involve population of 52, 480 students if the desired margin of error is 7%.

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Jessah Marie B.
Answer:

To determine the sample we will apply the Slovin's formula : $$ \frac{N}{1+Ne^2} $$ wherein N is the population and e is the margin of error. *Note that margin of error must be in decimal form. In the question N = 52, 480 and e = 0.07 Substituting the value in our formula : $$ \frac{52,480}{1+52,480(0.07)^2} $$ Answer : 203. 29 since we are looking for the sample size we need to round it up so our final answer is 204.

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