Tutor profile: Sam C.
What kind of hybridization is exspected for CH3CH2CH3, geometry, and bond angle?
Carbons can form three different hybridizations Sp3 where carbon has four single bonds, tetrahedral bond angle 109.5 Sp2 where carbon has two single bonds and one double bond, Trigonal Planer, bond angle 120 Sp where carbon has one triple bond and one single bond when CH3CH2CH3 is drawn out the first C is attached by a single bond to the other carbon and the same thing with the last H3C - CH2 - CH3 The middle carbon will have two hydrogens attached to it. Which will make all the carbons have four single bonds. This will make it a Sp3 hybridization, with a geometry of Tetrahedral and we can then say that the bond angles are 109.5 sense that is the angles of Tetrahedral geometry.
What type of Bonding is found in CH3CH2CH2CH2CH2CH3? A. Covalent B. Polar
The type of bonding that occurs is Covalent bonding this is because by definition covalent bonding is the sharing of electrons equally. All the bonds in the above equation are shared equally. A. Covalent - sharing of electrons equally B. Polar - sharing of electrons unequally
Subject: Basic Chemistry
In General Chemistry Lab students are given 12g of NaCl in a test tube that was measured out by the TA and it will be used during the lab. However, a student dropped a test tube and it broke spilling all of his sample. The student needs to measure out 12g of NaCl to being the experiment, but the scale being used only reads in moles. How many moelss of NaCl will the student need to measure out for the experiment? Record your answer with the correct number of significant digits.
First find the formula weight of NaCl Na - 22.99g Cl - 35.45g (keep in mind that all formula weights are in grams) Add Na and Cl together 22.99g + 35.45g So the formula weight of NaCl is 58.44g Then preform conversions from grams to moles 12g of NaCl x 1mol of NaCl / 58.44g of NaCl (make sure that grams canceled out leaving moles in the numerator) This should leave 0.21moles of NaCl To check this real quick we can solve for the original amount of NaCl in grams X x 1mol of NaCl / 58.44g NaCl = 0.21mol NaCl (multiply 0.21mol NaCl by 58.44g NaCl) X x 1mol NaCl = 0.21mol NaCl x 58.44g NaCl X x 1mol NaCl = 12mol / g NaCl (the divide by 1mol NaCl making sure to cancel out units) X = 12g NaCl (which is what was stated in the original problem so we are correct!)
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