What is the value of y when: 7-4+3x0+1=y ?
PEMDAS is an easy way to remember order of operations. Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction, in that order. The value of y=2 To solve for y, first multiply (3x0=0), then add (4+1=5) then subtract (7-5=2). The answer is 2.
A function f(x)=(x^2)-x+6 crosses the x-axis at what two points?
First factor the polynomial to (x-3)(x+2)=0. From here you can see that when x=3 or x= -2, f(x) =0. When f(x) crosses the x-axis, f(x) has to equal 0 so the points are (-2,0) and (3,0)
f(x)=2x+6, find a function g(x) that has a slope perpendicular to f(x).
A linear function is written in terms y=mx+b where m= the slope(rise over run) and b=the y-intercept. A slope perpendicular to m = - 1/m. So any function that has a slope of - 1/2 would be perpendicular to f(x). ex: g(x) = (-1/2)x+4