Tutor profile: Fatima W.
Find the dimensions of the rectangle that has a length 3 meters more that its width and a perimeter equal in value to its area?
Let L be the length and W be the width of the rectangle. L = W + 3 Perimeter = 2L + 2W = 2(W + 3) + 2W = 4W + 6 Area = L W = (W + 3) W = W2 + 3 W Area and perimeter are equal in value; hence W2 + 3 W = 4W + 6 Solve the above quadratic equation for W and substitute to find L W = 3 and L + 6
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