Enable contrast version

Tutor profile: Vikas J.

Online
Vikas J.
Tutor for more than 3 year . Teaching Calculus at multiple online tutoring platform before finding this cool place to teach .
Tutor Satisfaction Guarantee

Questions

Subject: Pre-Calculus

TutorMe
Question:

Determine the area of the region enclosed by y = sinx, y=cosx, x=π/2, and the y-axis.

Inactive
Vikas J.
Answer:

As we know at x = π/4 will be the intersection point for the two curves and also the position of the graph changes so we will find this integral in two parts : A = int. 0 to π/4 ( cosx - sinx ) + int. π/4 to π/2 ( sinx - cosx) = 0 to π/4 ( sinx + cosx ) + π/4 to π/2 ( -cosx - sinx ) = 2^(1/2) - 1 + 2^(1/2) - 1 = 2^(1/2) - 2 = 0.829

Subject: Calculus

TutorMe
Question:

Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the given curves about the y-axis. y = e^x, y = e^-x, x = 1; about the y-axis

Inactive
Vikas J.
Answer:

Volume = int. 2pix(e^x - e^-x) from 0 to 1 = 4pi/e

Subject: Algebra

TutorMe
Question:

If x^3 + y^3 = 9 and x + y = 3, then the value of x^4+y^4 is

Inactive
Vikas J.
Answer:

x^3+y^3 = (x + y) × (x^2 − xy + y^2) Putting given values of x^3+y^3 and (x + y) 9 = 3 × ((x+y)2 − 3xy) = 3 × (9 − 3xy) = 27 − 9xy 9xy = 18 xy = 2 x^4 + y^4 = (x^2 + y^2)2 - 2x^2y^2 = (x^2 + y^2)2 - 2*4 [Putting value of xy] = ((x + y)2 - 2xy)2 - 2*4 [Putting values of (x+y) and xy] = (9 - 4)2 - 2*4 = 17

Contact tutor

Send a message explaining your
needs and Vikas will reply soon.
Contact Vikas

Request lesson

Ready now? Request a lesson.
Start Lesson

FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.