Enable contrast version

Tutor profile: Rohit Y.

Inactive
Rohit Y.
Tutor for 3+ years.
Tutor Satisfaction Guarantee

Questions

Subject: Linear Algebra

TutorMe
Question:

T:R^{4} ---> R^{4}, defined by T(e_{1})=e_{2}, T(e_{2})=e_{3}, T(e_{3})=0, T(e_{4})=e_{3}. Where e_(i)'s are members of the basis, Then (a) T is nilpotent (b) T has at least one non-zero eigen value (c) index of nilpotent is three (d) T is not nilpotent

Inactive
Rohit Y.
Answer:

Answer is that: T is nilpotent with at least one nonzero eigen value and index of nilpotent is three! Hint: construct a matrix of T corresponding to the given linear transformation( if you take standard basis, to form a matrix, you will notice that all the eigen values are zero with certain power of matrix is zero. So clearly option (d) is not the case. For other option one needs to go with generalized proof, keeping in mind all the definitions required!

Subject: Pre-Algebra

TutorMe
Question:

The equation mx - 8 = 6 - 7(x + 3) DOES NOT have any solution if m = A. 3 B. 7 C. -7 D. 0

Inactive
Rohit Y.
Answer:

Answer is -7! As if we simplify above equation (given in question) and collect variable x on one side, it will become: mx-7x = 7, clearly for the value of m = -7, x vanishes and we will not be able to find its value!

Subject: Algebra

TutorMe
Question:

A group of order 505 is cyclic?

Inactive
Rohit Y.
Answer:

Group of order 101 is unique. Since that subgroup is unique, it is normal. So G has a normal subgroup of order 101 and a subgroup of order 5 (which might not be normal). If you consider Sylow theorems, you will be able to know that the groups of this type are called semidirect products determined by maps from Z/5 into Aut(Z/101)≃Z/100. There is a map from Z/5 into Z/100, and so we have a noncyclic group of order 505. To be more precise, it is: ⟨x,y:x5=1,y101=1,xy=y36x⟩

Contact tutor

Send a message explaining your
needs and ROHIT will reply soon.
Contact ROHIT

Request lesson

Ready now? Request a lesson.
Start Lesson

FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.