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# Tutor profile: Dhananjay K.

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Dhananjay K.
Teaching Physics and Maths for the last 15+ years.
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## Questions

### Subject:Physics (Newtonian Mechanics)

TutorMe
Question:

Find the maximum height attained by a ball thrown vertically upward with an initial velocity of 9.8m/s.

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Dhananjay K.

At the highest point the velocity of the ball becomes zero. So we have Final velocity v = 0m/s Initial velocity u = 9.8 m/s Acceleration of the ball a = -g = -9.8 m/s^2 Let the highest distance attained by the ball is s. Then applying the equation of motion v^2 = u^2 + 2as 0 = (9.8)^2 -2\times9.8\times s s = \dfrac{9.8^2}{2\times9.8} = 4.9 m

### Subject:Pre-Calculus

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Question:

Find the value of x e^(logx)=5

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Dhananjay K.

From the property of log we know that log(x)=y, implies e^y=x Therefore e^(logx)=5, implies log(5)=logx, hence x=5

### Subject:Basic Math

TutorMe
Question:

If x/y=5/2 find the value of (2x+3y)/(2x-3Y)

Inactive
Dhananjay K.

Given x/y=5/2 Multiplying the numerator by 2 and denominator by 3 on both sides of the above equaton 2x/3y=10/6 2x/3y=5/3 Applying componendo and dividendo (2x+3y)/(2x-3y)=(5+3)/(5-3) =8/2 =4

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