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# Tutor profile: Bryant C.

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Bryant C.
Practicing pharmacist, science & math tutor
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## Questions

### Subject:Pharmacy

TutorMe
Question:

Which of the following drugs has NOT been shown to decrease mortality in CHF? - carvedilol - ramipril - furosemide - spironolactone

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Bryant C.
Answer:

The beta-blockers carvedilol, metoprolol succinate, and bisoprolol, ACE inhibitors, and spironolactone have all demonstrated mortality benefit for most heart failure patients. Furosemide is commonly used in heart failure patients for symptom control (volume overload leading to edema, dyspnea, etc.) but does not have a mortality benefit.

### Subject:Basic Math

TutorMe
Question:

A telemarketer selling fruitcakes made 1,000 calls to random numbers. If 60% of the phone numbers were disconnected lines, half of the calls that rang were answered, 1/10th of the people answering the phone each made a purchase, and each purchase was for an average quantity of 1.5, how many fruitcakes did the telemarketer sell?

Inactive
Bryant C.
Answer:

This question requires multiple steps. 1,000 calls were made, but 60% were disconnected lines. 1000 x (1-60%) = 400 calls were to real phone numbers. Half the calls that rang were answered. 400 x 0.5 = 200 calls were answered. 1/10th of the people answering the phone made a purchase. 200 x (1/10) = 20 people made a purchase. Each purchase was for 1.5 fruitcakes. 20 x 1.5 = 30 fruitcakes were sold.

### Subject:Basic Chemistry

TutorMe
Question:

Which inorganic salt would have the greatest effect on the freezing point of water at a concentration of 1m? -NaCl -KI -CaCl2 -CaHPO4

Inactive
Bryant C.
Answer:

Freezing point depression can be calculated using the formula: ΔTf=kf⋅m⋅i where kf is a constant property of the solvent, m is the molality of the solution, and i is the number of dissociated ions per mol of solute. In the question, the only variable is i because the constant kf and the concentration are the same for all options. NaCl and KI both dissolve into two components so i=2. CaHPO4 is not soluble in water; therefore it will have negligible change on the freezing point. CaCl2 dissolves into 3 particles: one Ca2+ and two Cl-; therefore it will have the greatest effect on the freezing point of water.

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