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# Tutor profile: Arslan R.

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Arslan R.
I am Electrical Power Engineer having 5 years of working experience, and teaching Electrical , Physics and Mathematics from 4 Years.
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## Questions

### Subject:Applied Mathematics

TutorMe
Question:

Let f (x) = 4x2 + 9 and g(x) = x - 3. Find the composite function and simplify Find (F*G)(-1) = ?

Inactive
Arslan R.

Let f (x) = 4x2 + 9 and g(x) = x - 3. F*G = (4x2 + 9)*(x-3) F*G = 4x3-12x2+9x-27 (F*G)(-1) = 4(-1)3-12(-1)2+9(-1)-27 (F*G)(-1) = -4-12-9-27 (F*G)(-1) = -52

### Subject:Electrical Engineering

TutorMe
Question:

Consider solar cells are connected in two arrangements llike: Scenario A: Four series-connected cells in each column forming 4 column arrangement, one cell from column 3 and column 4 working on 75% efficiency, remaining working on 100% efficiency. Scenario B: 4th column series-connected solar cells have efficiency like : 1st = 50% , 2nd =80%, 3rd = 90%, 4th = 50%, remaining working on 100% efficiency. Voltage remain same and current varry with the variation of efficiency. Find Power in both scenario and comapre them ?

Inactive
Arslan R.

For two or more cells connected in series, the current through the two cells is the same. The total voltage produced is the sum of the individual cell voltages. Since the current must be the same, a mismatch in current means that the total current from the configuration is equal to the lowest current. Current in scenario A =1st Column +2nd Column + 3rd Column + 4th Coloumn Current in A = 1 +1+0.75+0.75 = 3.5 Power in A = VI = 3.5V Current in scenario B =1st Column +2nd Column + 3rd Column + 4th Coloumn Current in B = 1+1+1+0.5 = 3.5 Power in B = VI = 3.5V Therefore, Pa = Pb

### Subject:Physics

TutorMe
Question:

Find Equation for compression force and deform compression length when: First force was 2N and the second force was 14N and the length was 18mm.

Inactive
Arslan R.

Equation will be like: F = k x x=2/k ---- deformed length when 2 N force applied The force in the compression spring is found from Hooke's Law, F = k (Lfree - Ldeform) F = k (18- 2/k) = 18k -2 Again, F = k x x=14/k ---- deformed length when 14 N force applied F = k (Lfree - Ldeform) F = k (18- 14/k) = 18k -14 F1+F2 = 18k -2 + 18k -14 Compression force F1+F2 = 36k -16 Total compress in length due to both force: F = k x x = 36k -16 / k

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