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# Tutor profile: Simira C.

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Simira C.
Certified Math and Chemistry Teacher
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## Questions

### Subject:Basic Math

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Question:

Simplify the following expression 6^2-8*2+2(x-4)

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Simira C.

Order of Operations: PE MD (from right to left) AS (from right to left) 6^2-8*2+2(x-4) Parenthesis: Distribute 2(x-4) : 2x-8 6^2-8*2+2x-8 Exponent: 6^2 = 36 36-8*2+2x-8 Multiply: 8*2 = 16 36-16+2x-8 Add like terms: 36 +-16+ -8 = 12 2x + 12

### Subject:Chemistry

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Question:

Balance the chemical equation __H_{2} + __ O_{2} --> __ H_{2}O

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Simira C.

There are two O on the reactant side and one on the product side, so a coefficient of 2 is placed in front of H_{2}O in order to even out the oxygen. We now have four H on the product side and two on the reactant side so a coefficient of 2 goes in front of H_{2} to even them out. The equation is now balanced. 2H_{2} + O_{2} --> 2H_{2}O

### Subject:Algebra

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Question:

You are selling concessions at a basketball game. David purchased a hot dog and a drink for \$8.00. A family purchased 3 hotdogs and 4 drinks for \$29.00. What is the cost of one hot dog?

Inactive
Simira C.

First set variables, using h for hotdogs, and d for drinks. Equation 1 h + d = 8.00 Equation 2 3h + 4d = 29.00 -4h - 4d = -32 Multiply the first equation by -4 3h + 4d = 29 Subtract like terms -h = -3 Divide both sides by -1 to isolate h h = 3 Each hot dog costs \$3.00.

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