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Tutor profile: Ashita M.

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Ashita M.
Math Tutor for 4 years, Biomedical Engineer by profession.
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Questions

Subject:Trigonometry

TutorMe
Question:

In a right angled triangle, let one of the acute angles be X. A side opposite to X is 4mm, adjacent side is 3mm, and hypotenuse is 5 mm. Find values of sin X, cos X, tan X.

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Ashita M.

Let us represent opposite side by O, adjacent side by A and hypotenuse by H. Then, O=4, A=3, H=5. We know that, sin X = O/H = 4/5 cos X = A/H = 3/5 tan X = O/A = 4/3

Subject:Basic Math

TutorMe
Question:

Imagine you have a bag filled with 5 candies. Now, add 3 more candies to the bag. Then subtract 5 candies. Double this number. What is the final number of candies left in the bag?

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Ashita M.

5 candies ---- > O O O O O ADD 3 candies to 5 So, O O O O O + O O O = O O O O O O O O = 8 SUBTRACT 5 candies from 8 O O O O O O O O - O O O O O = O O O = 3 Double this number of candies 2 times O O O = O O O + O O O = O O O O O O = 6 So, the final number of candies left in the bag is 6.

Subject:Algebra

TutorMe
Question:

Solve for x. The equation is 2x + 4=10

Inactive
Ashita M.

The given equation is 2x + 4=10. Since, we want to find the value of x, our goal is to isolate x and keep it on one side of the equal to sign. This can be done by moving 4 to the right hand side of the equal to sign. So, we get 2x = 10-4 Next step is to subtract 4 from 10. 2x = 6 Observe that 2 is attached to x. So, to find the value of x, we need to get rid of 2. This can be done by dividing both sides of equal to sign with 2. we get, x = 6/2 = 3 Thus, x = 3.

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