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Tutor profile: Ingrid S.

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Ingrid S.
Experienced Teacher of High School Mathematics and Computer Science
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Questions

Subject: Basic Math

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Question:

If $$a*b = 2a + b$$ where $$*$$ is a binomial function, then what is $$5*8$$ ?

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Ingrid S.
Answer:

In this case, $$a = 5$$, so wherever we see $$a$$, we put $$5$$ instead. Also, $$b = 8$$, so wherever we see $$b$$, we put $$8$$ instead. $$5 * 8 = 2 \times 5 + 8 = 10 + 8 = 18$$ $$5 * 8 = 18$$

Subject: Databases

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Question:

Explain what a database is.

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Ingrid S.
Answer:

A database is a group of connected files where each file has at least one similar field.. For example, The Library's Borrowing Database, consists of 3 files the files are connected by one same field called the NAME field Personal Information File (has 3 fields - NAME, AGE and HOMETOWN) NAME - John. AGE - 15. HOMETOWN - Arima. NAME - Sarah. AGE - 18. HOMETOWN - Mayaro. Book Borrowed File (has 2 fields - NAME and BOOKTITLE) NAME - John. BOOKTITLE - Adventures Of Sherlock Holmes. NAME - sarah. BOOKTITLE - Little Women. A file consists of a group of fields. A field is a group of characters. A character is one letter (For example "J") OR one digit (For example "5") OR one symbol (For example "?")

Subject: Algebra

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Question:

Solve the following equation $$3x^2 + 7x + 2 = 0$$

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Ingrid S.
Answer:

The equation is in the form of $$ax^2 + bx + c = 0$$ We must find 2 numbers $$p$$ and $$q$$ that satisfy the following $$p \times q = a \times c$$ and $$p + q = b$$ $$a = 3$$ , $$b = 7$$, and $$c = 2$$ $$a \times c = 3 \times 2 = 6$$ What are the PAIR factors of 6? One pair of factors of 6 ARE 2 and 3 Let's check this Let $$p = 2$$ and $$q = 3$$. This means that $$p + q = 2 + 3 = 5$$ which is not equal to $$b$$ as $$b = 7$$ Another pair of factors of 6 ARE 1 and 6 Let's check this Let $$p = 1$$ and $$q = 6$$ This means that $$p + q = 1 + 6 = 7$$ which IS equal to $$b$$ So, we let $$p = 1$$ and $$q = 6$$ Now we write the equation in the form $$ax^2 + (p + q)x + c = 0$$ then factorize $$3x^2 + (1 + 6)x + 2 = 0$$ $$3x^2 + 1x + 6x + 2 = 0$$ $$(3x^2 + 1x) + (6x + 2) = 0$$ $$x(3x + 1) + 2(3x + 1) = 0$$ $$(3x + 1)(x + 2) = 0$$ $$3x + 1 = 0$$ and $$x + 2 = 0$$ When $$3x + 1 = 0$$ $$3x = -1$$ $$x = -1/3$$ When $$x + 2 = 0$$ $$x = -2$$ THE SOLUTIONS OF THE EQUATION $$3x^2 + 7x + 2 = 0$$ ARE $$x = -1/3$$ AND $$x = -2$$

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