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Tutor profile: Kaylin X.

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Kaylin X.
Tutor and Mentor for 5 years
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Questions

Subject: Organic Chemistry

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Question:

E2 is a very stereoselective reaction. What is the exact stereochemistry necessary for an E2 reaction?

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Kaylin X.
Answer:

The H must be antiperiplanar to the leaving group.

Subject: French

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Question:

Identifiez et corrigez la faute dans la phrase suivante: Je dois prendre le bus parce que je n'ai pas un vélo.

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Kaylin X.
Answer:

La phrase correcte: Je dois prendre le bus parce que je n'ai pas DE vélo. Dans une phrase négative ("je N'ai PAS), l’article indéfini (un, une ou des) est remplacé par la préposition DE. L'exception est si le verbe dans la phrase est le verbe "être". Dans ce cas-là, on peut utiliser l’article indéfini (un, une ou des) dans une phrase négative: Ce n'est pas UN vélo. ENGLISH: The correct sentence: Je dois prendre le bus parce que je n'ai pas DE vélo. In a negative sentence ("je N'ai PAS), the indefinite article (un, une or des) is replaced by the preposition DE. The exception is if the verb in the sentence is the verb "être". In that case, we can use the indefinite article (un, une or des) in a negative sentence: Ce n'est pas UN vélo.

Subject: Pre-Calculus

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Question:

Evaluate sin(7π/12) exactly using the identity sin(A+B) = sinAcosB + cosAsinB

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Kaylin X.
Answer:

The key here is to realize this: sin(7π/12) = sin(π/4 + π/3). After realizing that, the rest of the problem isn't too hard; just plug everything into the given identity: sin(π/4 + π/3) = sin(π/4)cos(π/3) + cos(π/4)sin(π/3) = (√2/2 • 1/2) + (√2/2 • √3/2) = √2/4 + √6/4 = (√2+√6)/4. You might ask yourself: How in the world was I supposed to realize that sin(7π/12) = sin(π/4 + π/3)? The hint is given in the problem itself. Knowing that you have to use the identity sin(A+B) is the hint that you should convert sin(7π/12) into the form sin(A+B), so by splitting the fraction 7π/12 into A and B. Furthermore, knowing that you're supposed to evaluate the question exactly (without a calculator) is a hint that A and B will be recognizable, "easy to work with" fractions, which can help you split 7π/12 into π/4 and π/3.

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