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# Tutor profile: Thu N.

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Thu N.
A Financial Analyst who have a great passion for Math/Data
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## Questions

### Subject:Pre-Calculus

TutorMe
Question:

expand logarithm: $$\log_4(\frac{2^2}{3})^3$$

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Thu N.

$$\log_4(\frac{2^2}{3})^3$$ = $$3 \log_4(\frac{2^2}{3})$$ = $$3(\log_42^2 - \log_43)$$ = $$3\log_44 - 3\log_43$$ = $$3 - 3\log_43$$

### Subject:Pre-Algebra

TutorMe
Question:

solve for x and y: $$5x^{2} - 3y = -15$$ $$2x + y = 5$$

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Thu N.

$$5x^{2} - 3y = -15$$ (1) $$2x + y = 5$$ (2) (1) $$-> y = 5 - 2x$$ so (2) : $$5x^{2} - 3*(5 - 2x) = -15$$ $$5x^{2} - 15 + 6x = -15$$ $$5x^{2} + 6x = -15 + 15$$ $$5x^{2} + 6x = 0$$ $$x(5x + 6) = 0$$ $$-> x = 0$$ or $$5x + 6 = 0$$ $$x = 0$$ or $$x = -6/5$$

### Subject:Algebra

TutorMe
Question:

Simplify to lowest terms: $$\frac{x^8+a^3 * x^4 * y}{x^8-a^6 * y^2 }$$

Inactive
Thu N.

$$\frac{x^8+a^3 * x^4 * y}{x^8-a^6 * y^2 }$$ = $$\frac{x^4*(x^4 + a^3 * y)}{(x^4)^2 - (a^3 * y)^2 }$$ = $$\frac{x^4*(x^4 + a^3 * y)}{(x^4 + a^3 * y)* (x^4 - a^3 * y) }$$ = $$\frac{x^4}{(x^4 - a^3 * y) }$$

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