If f(x)=x^2-4x+6 and g(x)=2x^2, then f(g(x))=
Since g(x) is the inside function, we will be plugging in 2x^2 into the f(x) equation. Once we plug g(x) into f(x), we obtain (2x^2)^2-4(2x^2)+6, which is 4x^4-8x^2+6.
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Evaluate integral of lnxdx.
The integral of lnxdx could be solved by using integration by parts. We could let u=lnx and dv=1dx so that du=(1/x)dx and v=x. By plugging these values into the integration by parts formula, we will realize that the integral of lnxdx is xlnx-x+c.