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Tutor profile: Ashley T.

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Ashley T.
Tutor for 3 years
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Questions

Subject: Study Skills

TutorMe
Question:

What should you not do the night before a test: A. Get 8+ hours of sleep. B. Cram and try to learn everything. C. Eat a well-balanced meal. D. Get your stuff ready for the morning.

Inactive
Ashley T.
Answer:

The night before a test, you should always try to get 8+ hours of rest. It is proven that a lack of sleep will reduce your mental performance the next day, so don't risk it. You should slowly be studying for an exam and reviewing material starting a week or more before the exam. This will give you time to find things you don't understand or forgot so you have time to refresh your memory and/or relearn material. Never try to cram the night before. You can review once more, but you should not be learning new material. Also, if you are cramming, you are most likely not going to be able to get a good 8+ hours of sleep. You should definitely eat a well-balanced meal the night before a test and a good meal on the morning of your test. It is proven that what you eat will have an effect on your mental and physical performance. Getting your stuff ready for the morning will allow you to have a stress free morning and you will be able to relax and focus on your test. Pack a bottle of water and make sure you have all the materials needed, including pencils and erasers. If a calculator is allowed, make sure it is charged and you pack extra batteries. If a laptop is allowed, make sure it is fully charged and to bring a charger. The correct answer to the problem is B. Do NOT cram the night before the test!

Subject: ACT

TutorMe
Question:

If r= 8, b= 2, and g= -5, what does (r+b-g)(b+g) equal? A. 36 B. 24 C. 45 D. 65 E. -24

Inactive
Ashley T.
Answer:

To begin, we will plug in the values of r, b, and g into the equation. Since they are all given, we don't have to solve for anything. After plugging the numbers, in, we get (8 + 2 - (-5))(8+(-5)). Remember that if you subtract a negative number, you add them. Two negatives become a positive. We can change our equation to be: (8+2+5)(8+(-5)). Next, we simply add the numbers inside the parenthesis. 8+2 equals 10. 10+5 equals 15. 8+(-5) can be rewritten as 8-5, so we get 3. Now our equation will look like (15)(3). When two numbers have surrounded by parenthesis are right next to each other, we multiply. 15*3 = 45, which is our answer!

Subject: Algebra

TutorMe
Question:

Factorise x^2 +9x + 20

Inactive
Ashley T.
Answer:

To begin, we must first consider all the factors of 20. What numbers can we multiply together to get 20? 1 and 20 2 and 10 4 and 5 Now that we have all the possibilities, we have to look at the signs. Since all the numbers in the equation are positive, we look at the factors above to see which ones add up to 9. We see that 4 and 5 add up to 9. This means we can factor the equation to be: (x+4)(x+5). To check our work, we can use the FOIL method: First Outer Inner Last. We first multiply x*x to get x^2. That is good! We have an x^2 in our original equation! Next, we multiply x by 5, which are our outer numbers. This equal 5x. We will put this to the side for now. Now we will multiply 4*x. These are our two inside numbers right next to each other. That equals 4x. Finally, we multiply 4*5, out last two numbers. This equals 20. We add all of these together to get: x^2 + 5x + 4x + 20 The last thing we need to do to check is to combine the terms that are similar. x^2 does not combine with anything so we leave it be. We can combine 5x and 4x because they both have x's. This equals 9x. 20 does not combine with anything so we leave it alone too. Out final equation equals x^2+9x+20, which is the same as the original equation, so we know we factored correctly! Great job!

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