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Lindsey S.
4+ years of tutoring experience, majoring in Secondary Education-Mathematics
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Geometry
TutorMe
Question:

1.) What is the sum of the interior angles of a regular hexagon? 2.) If a 45-45-90 triangle has a hypotenuse with the length of 8, what are the measures of the two legs? 3.) If a circle has an inscribed angle of 48 degrees, what is the measure of the intercepted arc?

Lindsey S.

1.) Use the formula $$(N-2)(180)$$ to find the sum of the interior angles: $$(6-2)(180)$$ $$(4)(180)$$=$$720$$ 2. Step 1: Set $$L\sqrt{2}=hypotenuse$$ and solve/simplify $$L\sqrt{2}=8$$ Step 2: Solve for "$$L$$" $$L=\frac{8}{\sqrt{2}}$$ $$L=\frac{8}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}$$=$$\frac{8\sqrt{2}}{\sqrt{4}}$$=$$\frac{8\sqrt{2}}{2}$$=$$4\sqrt{2}$$ 3.) The measure of an intercepted arc is the measure of the inscribed angle times 2, therefore: $$48*2=96 degrees$$

English
TutorMe
Question:

1.) Define the prepositional phrase in the following sentence: The English notes in Lindsey's binder are outdated. 2.) Indicate whether "who" or "whom" should be inserted in the blank: The girl ______ you met yesterday is moving away. 3.) Indicate which word in the sentence is an adjective and which word is an adverb: Lindsey handled the breakable toy very carefully.

Lindsey S.

1.) in Lindsey's binder (describes which notes we were talking about) 2.) whom 3.) "breakable" is the adjective and "very" is the adverb

Algebra
TutorMe
Question:

1.) Solve the equation: $$5(-3x-2)-(x-3)=-4(4x+5)+13$$ 2.) Solve the equation: $$2x=\sqrt{x+3}$$ 3.) Find the slope: $$(-2,4) , (1, 10)$$

Lindsey S.

1.) Step 1: Distribute/multiply the factors $$-15x-10-x+3=-16x-20+13$$ Step 2: Group the like terms $$-16x-7=-16x-7$$ Step 3: Add $$16x+7$$ to both sides of the equation, therefore $$0=0$$ Therefore, the statement is true for all real number values of x 2.) Step 1: Square both sides of the equation $$(2x)^2=(\sqrt{x+3})^2$$ $$4x^2=x+3$$ Step 2: Move everything to one side of the equation (equal sign) so 0= $$4x^2-x-3=0$$ Step 3: Find factors for quadratic equation $$(4x+3)(x-1)=0$$ Step 4: Solve for $$x$$ $$4x+3=0 ; x-1=0$$ $$4x=-3 ; x=1$$ $$x=-\frac{3}{4} ; x=1$$ 3.) Step 1: Use the slope formula to find the slope $$m=\frac{y_2-y_1}{x_2-x_1}$$ $$m=\frac{10-4}{1-(-2)}$$=$$\frac{6}{3}$$=$$2$$

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