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Amanda C.
Talented Tutor
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SAT
TutorMe
Question:

Either you _______________ your behavior or I will be forced to _______________ you. A. Condemn ... authorize B. Corrupt ... salute C. Improve ... reprimand D. Descend ... serene E. Negligent ... promote

Amanda C.
Answer:

The SAT is not necessarily testing crude knowledge, but the ability to take tests. To find the answer to this question, regardless of whether or not you know the meaning of all of the words available, you must look at the context clues. Since forced describes the second blank, you will assume that the second word needs to have a negative connotation. Since the second word is negative, the first must be positive. Only C has a positively-charged first word and negatively-charged second word, and it is the correct response.

Basic Math
TutorMe
Question:

If Stacey has 7 $20 bills, 9 $10 bills, 13 $5 bills, 27 $1 bills, 11 quarters, 2 dimes, 4 nickels, and 21 pennies, how much money does Stacey have?

Amanda C.
Answer:

In order to solve this problem, you should first find the products before finding the sum. Since she has 7 $20 bills, you multiply 7 by 20 to get 140. Since she has 9 $10 bills, you multiply 9 by 10 to get 90. Since she has 13 $5 bills, you multiply 13 by 5 to get 65. Since she has 27 $1 bills, you multiple 27 by 1 to get 27. Since she has 11 quarters, you multiply 11 by 0.25 to get 2.75. Since she has 2 dimes, you multiply 0.10 by 2 to get 0.20. Since she has 4 nickels, you multiply 0.05 by 4 to get 0.20. Since she has 21 pennies, you multiply 0.01 by 21 to get 0.21. Now that you have found all of the products, you add them all together to get the total sum of money that Stacey has. Adding the product of the $20 bills to the product of the $10 bills is 140 plus 90, which gets you 230. Adding the sum of the $20 bills and $10 bills to the product of the $5 bills is 230 plus 65, which gets you 295. You continue this pattern until all of the products are added together to calculate the grand total of $325.36.

Chemistry
TutorMe
Question:

If you react 32 g of CH4 with 64 g of O2, which is the limiting reagent?

Amanda C.
Answer:

To begin this problem, it is necessary to first write out a balanced chemical equation. This reaction is a typical combustion reaction, so carbon dioxide and water will be products. The balanced equation turns out to be CH4 + 2O2 --> CO2 + 2H2O. Next, we must find the mole ratio. According to the balanced equation, in order for a reaction to occur, there must be 2 moles of oxygen for 1 mole of methane. Now we need to calculate how many moles of each reactant we have. The molar mass for methane is 16 g, and since we have 32 g, we have 2 moles of methane. The molar mass for oxygen is 32 g, and since we have 64 g, we also have 2 moles of oxygen. According to the mole ratio, in order for all of the methane to react, we would need 4 moles of oxygen. Since all of the oxygen would be used up and some methane would be leftover, oxygen is the limiting reagent.

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