Enable contrast version

Tutor profile: Liz C.

Inactive
Liz C.
Certified K-12 Math Teacher, Private Tutor for 22 years
Tutor Satisfaction Guarantee

Questions

Subject: Pre-Calculus

TutorMe
Question:

Solve the equation -10 + 3e^x = -6

Inactive
Liz C.
Answer:

The first step in solving our equation is to move the -10 to the other side of the equal sign. We need to perform the opposite operation, so we should add 10 to the -6 to get 4. Next, divide by 3 to get the e term by itself. We get e^x = 4/3. In order to eliminate the e, we find the natural log of both sides, since e and ln are inverses of each other. This eliminates the e on the left and gets the x by itself. The natural log of 4/3 is 0.2877, so this is the solution for x.

Subject: Geometry

TutorMe
Question:

A right triangle has legs of length 5 cm and 7 cm. Find the missing hypotenuse.

Inactive
Liz C.
Answer:

We use Pythagorean Theorem to find missing side lengths in a right triangle. The theorem is a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse. In this triangle, a and b are 5 cm and 7 cm. Plug these into the formula and we get 25 + 49 = c^2. Add 25 and 49 to get 74. To find c, we need to take the square root of 74. 74 does not have a perfect square root, so we can round the answer to 8.6 cm.

Subject: Algebra

TutorMe
Question:

Solve the equation by factoring: x^2 + 7x = 8

Inactive
Liz C.
Answer:

In order to solve by factoring, the equation must be set equal to zero. So we need to move the 8 over to the left hand side of the equal sign. When we move it, we perform the opposite operation, so we must subtract 8. The equation is now x^2 + 7x - 8 = 0. To factor, we should look for factors of -8 that add up to 7. That would be 8 and -1. Set up our 2 sets of parentheses with these factors. Remember that since our leading term is x^2, the leading term in each set of parentheses must be x. So we have (x + 8) (x - 1) = 0. Now set each of those factors equal to zero and solve for x. X + 8 = 0, so x = -8, and x - 1 = 0, so x = 1. Our 2 solutions are -8 and 1.

Contact tutor

Send a message explaining your
needs and Liz will reply soon.
Contact Liz

Request lesson

Ready now? Request a lesson.
Start Lesson

FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.