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Sourabh K.

Tutor for 5 years

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Trigonometry

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Question:

The area of a right triangle is 50. One of its angles is 45o. Find the lengths of the sides and hypotenuse of the triangle.

Sourabh K.

Answer:

The triangle is right and the size one of its angles is 45 degree ; the third angle has a size 45 degree and therefore the triangle is right and isosceles. Let x be the length of one of the sides and H be the length of the hypotenuse. Area = (1/2) x Square = 50 , solve for x: x = 10 We now use Pythagoras theorem to find H: x square + x square = H square Solve for H: H = 10 sqrt(2)

Electrical Engineering

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Question:

If collector current Ib is 100uA and Beta = 100 .Calculate Ie

Sourabh K.

Answer:

We Know Ie = Ic+Ib and Ic = Beta * Ib hence Ie = ( Beta + 1 ) * Ib = 101 * 100 u = 10.1 mA

Algebra

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Question:

If x <2, simplify |x - 2| - 4|-6|

Sourabh K.

Answer:

Given the expression |x - 2| - 4|-6| STEP 1. If x < ;2 then x - 2 < 2 and if x - 2 < 2 the |x - 2| = -(x - 2). STEP 2. Substitute |x - 2| by -(x - 2) and |-6| by 6 . |x - 2| - 4|-6| = -(x - 2) -4(6) = -x -22

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