Tutor profile: Edith V.

Create a function that contains an integer parameter to check if that integer is an odd number. The function should return true if it is odd. Otherwise, it should return false.

To check if a number is odd, you can use the modulo (%) operator. If the number is even, we know that the number can not be odd. We can use the expression: number % 2 == 0 to check if the number is even. If the expression is not equal to 0, the number must be odd. If the number was 3, we would calculate 3%2. We know that the modulo operator returns the remainder of 3 divided by 2 which equates to 1 remainder 1. 1 is not equal to 0 and that makes the number odd. On the other hand, if the number was 2, we would calculate 2%2. 2 divided by 2 equates to 1 remainder 0. 0 equals 0, signifying that 2 must not be an odd number. def isOdd(x): if (x % 2 == 0): return false return true

What is a constructor?

A constructor is a piece of code that initializes a newly-created object. It initializes the fields (variables of the class) to default values. This is executed whenever a new instance of the class is created.

Your friend, Mark, has 12 coins in his pocket. The 12 coins are either quarters or dimes. The 12 coins add up to $10 in value. How many of each coin does he have?

Let q = the number of quarters Let d = the number of dimes Since there are 40 coins total, we can represent the number of quarters in terms of dimes with the equation: Equation 1: q = 40 - d If Mark had one dime, he would have 10 x 1 = 10 cents. If Mark had two dimes, he would have 10 x 2 = 20 cents. This relation can be represented as 10 x d = 10d where d represents the number of dimes. Similarly, 25q can be used to represent the quarter relation. We know that there are a certain number of dimes and quarters that add up to the total value of $10. Since our dime and quarter relations are in terms of 10 and 25, respectively (rather than 0.10 and 0.25), the total value will be increased by a factor of 100. So 10 x 100 = $1000 total. So, we can create an equation: Equation 2: 10d + 25q = 1000 With the two equations, we can substitute equation 1 into equation 2. 10d + 25(40 - d) = 1000 Then, distribute the numbers to get rid of the parentheses. 10d + 1000 - 25d = 1000 Add like terms. -15d + 1000 = 1000 Subtract 1000 from both sides. -15d = 0 Divide each side by -15. d = 0. Thus, there are 0 dimes. Plug in the d value to the equation 1 to find out the number of quarters. q = 40 - 0 q = 40 Thus, there are 40 quarters and 0 dimes. To check, we know that 40 quarters is 40 x 0.25 = 10 which is the total value stated in the problem. Thus, this solution is correct.