# Tutor profile: Melanie M.

## Questions

### Subject: Basic Math

Multiply 367 by 82.

To complete this problem, we must first stack the terms vertically, making sure to line up the ones place values in both numbers. 367 x 82 First, we multiply all the digits in the top number by the digit in our ones place in the second number and we do so starting with the ones place in the top number and working left. Therefore, we would start with 7x2. We would place the 4 in the ones place of our answer and carry the 1 ten. We would then move to multiplying the 6 in the tens place by 2, which equals 12 and adding in the 1 ten that was carried over (answer: 13). We would record the 3 in the tens place of our answer and carry the 1 ten. Next, we would multiply the 3 in the hundreds place of our top number by 2, and then add the 1 ten that was carried over (answer: 7). We would record the 7 in the hundreds place of our answer. Our equation should look as so: 367 x 82 ------- 734 Before moving on to multplying the 8 in the tens place of our second number by the digits in our top number, we must place a 0 in the ones place below our first answer. This place holder is added because we are now multiplying the tens place of our second number. Our equation should look as so: 367 x 82 ------- 734 0 We then continue by multiplying the 8 in our second digit by each digit in our top number, moving from right to left. We recognize 8x7 as 56. We place the 6 in our tens place in the second row of our answer and carry the 5. We recognize 6x8 as 48, adding in the 5 tens we carried, which is 53. We record the 3 in the hundreds place in the second row of our answer and carry the 5 tens. We recognize 8x3 as 24, adding in the 5 tens carried over, which is 29. We record the 9 in the thousands place of our second row answer, and our 2 in the tens thousands place. Our equation should look as so: 367 x 82 ------- 734 29360 To complete the equation, we add both products together (734 + 29,360). This gives us a final product of 30,094.

### Subject: Education

Does inclusive education promote successful learning? How?

Inclusive education promotes successful learning on various fronts. While inclusive education is a term mostly geared towards those with special needs, it's concept is to provide a learning experience for students that allows to learn in a way that fits them best. This includes a pace appropriate for the individual student, providing tools and topics that engage the student, and adjusting the learning to the student's needs rather than the needs of the administration or testing.

### Subject: Algebra

Solve for c. -4c+18 = -20-6c

In order to solve for c, we must first get all like terms to one side. Therefore, all terms involving c can be moved to the left of the equal sign and all terms without c can be moved to the right side of the equal sign. To complete this, we would first add 6c to both sides of the equation. This will negate the 6c on the right side of the equal sign, leaving -20. When 6c is added to the -4c on the left side of the equal sign, we will get a sum of 2c. Our equation will now look like this: 2c+18 = -20 We now must move 18 to the right side of the equal sign as it is not the same term as 2c. To cancel the 18 on the left side, we must subtract 18 from both sides of the equal sign. -20-18 then leaves us with -38 on the right side. Our equation will now look like this: 2c = -38 In order to get c alone, we must get rid of the 2 within the term. In order to do this, we must do the inverse operation to multiplication, which is divide, to both sides of the equation (2c indicates 2 multiplied by the value of c). By dividing 2c by 2, we cancel out the 2 and are left with c. We then must divide -38 by 2, which is -19. Therefore, c = -19.

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