Write the formula for the following compound: Silver (II) phosphate
First, write the symbols/formulas for each substance in the compound and their oxidation numbers. The Roman numeral after the silver tells you that the charge on silver is +2. The oxidation number for phosphate is -3; phosphate is a polyatomic ion and this oxidation number will be found in a textbook. Ag+2 PO4 -3 Next, put parentheses around your polyatomic, but leave out the charge... Ag +2 (PO4) -3 Now, criss-cross your charges - bring only the number and not the charge. Move the 3 down next to silver, and move the 2 down and next to phosphate. Ag3 (PO4)2 (final answer)
Given the following equation, N2 + H2 --> NH3, complete the following question. If 10 grams of nitrogen reacts with excess hydrogen, how much ammonia will be formed?
First, we must recognize that this is a stoichiometry problem. To complete a stoichiometry problem, you must have a balanced chemical equation. So let's balance the equation... 1 N2 + 3 H2 --> 2 NH3 Next, we will use the box method to complete the stoichiometric calculation.
Solve the equation 5(-3x - 2) - (x - 3) = -4(4x + 5) + 13
First, we need to remember PEMDAS (Parentheses, Exponents, Multiplication/Division, Addition/Subtraction)