Enable contrast version

Tutor profile: Laurel B.

Laurel B.
High School Math Teacher

Questions

Subject:Trigonometry

TutorMe
Question:

Given that sinA = 8/17, find angle A.

Laurel B.

To find angle measures using trigonometric ratios, take the inverse of the trig function. Given that sinA=8/17, the inverse sine of A = sin^-1(8/17) = 28, therefore Angle A = 28 degrees.

Subject:Geometry

TutorMe
Question:

Given the base angle of an isosceles triangle is 56 degrees, find the measures of the other two angles.

Laurel B.

Because the triangle is isosceles, the base angels are congruent. Therefore, one other angle is 56 degrees. The three angles of a triangle add up to 180 degrees. 180-56-56 = 68 degrees. Angle 1 = 56 degrees Angle 2 = 56 degrees Angle 3 = 68 degrees

Subject:Algebra

TutorMe
Question:

Find the slope of a line using points A (3,5) and B (2, 1).

Laurel B.

The slope of a line is how steep the line is, or how much it rises (vertical) over its run (horizontal). Slope is calculated as "rise" over "run", or the change in the y direction divided the change in the x direction. To calculate the slope between two points, first label the coordinates of each point as (x1, y1) and (x2,y2). Using the slope formula of (y2-y1)/(x2-x1), plug in your points and calculate the slope. A (3,5) 3 = x1, 5 = y1. B (2,1) 2 = x2, 1 = y2. (1-5)/(2-3) = -4/-1 = 4. The slope of the line is 4.

FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.
BEST IN CLASS SINCE 2015
TutorMe homepage