TutorMe homepage

SIGN IN

Start Free Trial

Jurgen X.

Tutor for 3 years

Tutor Satisfaction Guarantee

Pre-Calculus

TutorMe

Question:

\newline a) Find the domain of $f(x)=\sqrt{2x-4}+ln(3-x)$

Jurgen X.

Answer:

\newline a) For $\sqrt{2x-4}$, the condition is $2x-4\geq0$ which leads to $x\geq2$. For $ln(3-x)$, the condition is $(3-x)>0$ which leads to $x<3$. Therefore, the domain is $[2,3)$

Geometry

TutorMe

Question:

\newline a) What is the area of rhombus $ABCD$ with \angle ABC being 90 $^{\circ}$ and AB being 5cm long?

Jurgen X.

Answer:

\newline a) Since one of the rhombus' angles is a right angle, then the angle facing it is a right angle too. Since two angles next to each other add up to 180 $^{\circ}$ in a rhombus, then the other two angles are 90 $^{\circ}$ each. That means $ABCD$ is actually a square. Therefore we can easily find the area $5\times 5 = 25cm^2$

Algebra

TutorMe

Question:

\newline This is a sample question for Algebra: \newline a) Does the line $y= \frac{2}{3}x-6$ intersect with line $2y+3x=7$ ? If so, find the angle. If not, explain why in a sentence or two. \newline b) What are the coordinates of the common point (s) for these two lines? If there is no common point, what can we change to make them intersect?

Jurgen X.

Answer:

\newline a) Slope for the first line is $m_{1}=\frac{2}{3}$ and slope to second line is $m_2=\frac{-3}{2}$. Then we calculate the product $m_{1}\times m_{2}=-1$. Since the product of two slopes is $-1$, then the lines do intersect and they are perpendicular, therefore the angle is 90$^{\circ}$. \newline b) We start by plugging in $\frac{2}{3}x-6$ for $y$ in the second line's equation and we get $2\times [\frac{2}{3}x-6] +3x=7$. Solving for $x$, we get $x=\frac{57}{13}$. Substituting $\frac{57}{13}$ in the equation of first (or second) line, we find $y=\frac{-40}{13}$. Finally, the solution is ($\frac{57}{13}$;$\frac{-40}{13}$).

Send a message explaining your

needs and Jurgen will reply soon.

needs and Jurgen will reply soon.

Contact Jurgen

Ready now? Request a lesson.

Start Session

FAQs

What is a lesson?

A lesson is virtual lesson space on our platform where you and a tutor can communicate.
You'll have the option to communicate using video/audio as well as text chat.
You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.

How do I begin a lesson?

If the tutor is currently online, you can click the "Start Session" button above.
If they are offline, you can always send them a message to schedule a lesson.

Who are TutorMe tutors?

Many of our tutors are current college students or recent graduates of top-tier universities
like MIT, Harvard and USC.
TutorMe has thousands of top-quality tutors available to work with you.

Made in California

© 2019 TutorMe.com, Inc.