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Tutor profile: Anna B.

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Anna B.
Educator and Youth Development Professional. Experience Tutoring Middle Schoolers and High Schoolers.
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Questions

Subject:Pre-Algebra

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Question:

How do I solve an algebraic equation with one variable?

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Anna B.

Let's work with this example: 25 = 5 + 5x When we're working with an equation, we want to remember to do the same thing to both sides of the equation (both sides of the = sign). We're trying to solve for x, meaning we need to figure out what value the variable x represents. In order to do that, we need to isolate the variable. When we've solved the equation, x will be on one side of the equation (one side of the = sign) and the value of x will be on the other side. First, identify like terms. 5 and 5x are not like terms. We can't simplify the equation by adding them together. But, 25 and 5 are like terms. If we moved 5 to the other side of the equation, 25 and 5 could be combined to simplify the equation. If we subtract 5 from both sides of the equation, it brings the 5 from the right side of the equation to the left side. 25 − 5 = 5 + 5x − 5 Like we said before, 5 can be subtracted from 25, because they are like terms. The 5 on the right side of the equation is canceled out. 20 = 5x We're a step closer to isolating x. 5 is a coefficient of the variable x. 5 and x are attached by multiplication. In order to separate them, we have to do the inverse of multiplication – division. Since we have to do the same thing to both sides of the equation, let's divide both sides by 5. 20 ÷ 5 = 5x ÷ 5 4 = x We've finished solving the equation. The value of x is 4.

Subject:Basic Math

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Question:

How do you divide a fraction by another fraction?

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Anna B.

Let's say you have this problem: $$\frac{4}{5}$$ ÷ $$\frac{3}{4}$$ Dividing fractions looks intimidating, but with one simple step, it becomes a multiplication problem. When you're dividing two fractions, flip the second fraction by switching the numerator and the denominator, and change the division symbol to a multiplication symbol. $$\frac{4}{5}$$ ÷ $$\frac{3}{4}$$ becomes $$\frac{4}{5}$$ × $$\frac{4}{3}$$ Then, you can multiply across the numerator and the denominator, like you've done to multiply fractions before. $$\frac{4}{5}$$ × $$\frac{4}{3}$$ = $$\frac{16}{15}$$ Our numerator and denominator don't share any common factors, so we can't simplify this fraction any further, but, we can represent it as a mixed number. $$\frac{16}{15}$$ = 1 $$\frac{1}{15}$$

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Anna B.

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