Enable contrast version

Tutor profile: Aidin B.

Inactive
Aidin B.
Master's student in Math; B.S. in Physics; Love teaching
Tutor Satisfaction Guarantee

Questions

Subject: Basic Math

TutorMe
Question:

How far out would it reach out if would stack (end-to-end) all the people on Earth on each other?

Inactive
Aidin B.
Answer:

Currently, there are 7.8 billion people living on Earth. The average height of a person in 165 cm. So, the total length will be: $$7.8 \cdot 10^9 \cdot 1.65 \ m \approx 10^{10} m = 10^7 km$$

Subject: Physics

TutorMe
Question:

What is the gravitational acceleration on Mars?

Inactive
Aidin B.
Answer:

We can calculate the gravitational acceleration using the Law of Gravity: $$F_G = - \gamma \frac{M_{marse} m}{r^2}$$, where $$\gamma$$ is the gravitational constant. This force is equal to $$-mg_{mars}$$. So, we get: $$g_{mars} = \gamma \frac{M_{marse}}{r^2} $$. Using, the mass of Mars and its radius, we have: $$g_{mars} = 3.7 \frac {m} {s^2}$$

Subject: Algebra

TutorMe
Question:

Why are the solutions to the quadratic equation are what they are (quadratic formula)? How to derive the solution?

Inactive
Aidin B.
Answer:

Given a quadratic equation in general form: $$ ax^2 + bx+c=0 $$. The idea of the solution is to complete the square. More, precisely if $$a \ne 0$$: $$ax^2 + bx+c=a(x^2 + \frac{b}ax + \frac{c}a ) = a((x + \frac{b}{2a})^2 + \frac{c}a - \frac{b^2}{4a^2} ) = 0 $$. Thus, $$(x + \frac{b}{2a})^2 = -\frac{c}a+ \frac{b^2}{4a^2} \leftrightarrow x = -\frac{b}{2a} \pm \sqrt{\frac{b^2-4ac}{4a^2}}$$. Or, finally: $$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} $$

Contact tutor

Send a message explaining your
needs and Aidin will reply soon.
Contact Aidin

Request lesson

Ready now? Request a lesson.
Start Lesson

FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.
BEST IN CLASS SINCE 2015
TutorMe homepage
Made in California by Zovio
© 2013 - 2021 TutorMe, LLC
High Contrast Mode
On
Off