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John M.

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Pre-Calculus

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Question:

Find the vertex of the parabola y=2x^2-8x+7$.

John M.

Answer:

We have that x={b}/{2a}=-(-8)/(2*2)=2 y=2(2^2)-8(2)+7=8-16+7=-1

Calculus

TutorMe

Question:

If you have only 100 yards of fencing and want to make the largest area of a rectangle, What dimensions would you use for the fence.

John M.

Answer:

First you would make two equations. One for area and one for perimeter. L*W=A (2*L)+(2*W)=P P=100 Solve for L (100-2W)/2=L Substitute that equation into the Area Equation ((100-2W)/2)*W=A 50W-W^2=A differentiate 50-2W=A' Set A'=0 solve for w which is 25. Use original equation to find the length is also 25

Algebra

TutorMe

Question:

Find the equation that passes through the following 2 points: (-1,1) and (2,2)

John M.

Answer:

1. Find the slope of the line This is done by using (y1-y2)/(x1/x2) So for this it would be (1-2)/(-1-2)=(1/3) Next we have to plug in one of the points to find the y intercept for the equation y=mx+b we can use either of the two points to find b 2=((1/3)*2)+b Now we solve for b 2=(2/3)+b 1+(1/3)= b

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