What is the perimeter and area of a rectangle with a width of 5 inches and a length of 7 inches?
Perimeter(P) is equal to 2 times the length plus 2 times the width. Area(A) is equal to the width times the length. P= 2(5)+2(7)= 10+14=24 inches A= 5x7 = 35 inches
(−2x^2 +6x +1)−2(4x^2 −3x +1)=
First, Distribute the -2 over (4x^2 - 3x +1): -2x^2+6x+1-8x^2+6x-2 Combine the coefficients (numbers in front) of the x^2: -10x^2+6x+1+6x-2 Combine the coefficient of the x's: -10x^2+12x+1-2 Comine the final numbers: -10x^2+12x-1 Answer: -10x^2+12x-1
x^2 + 2x = 9 solve for x.
First, put everything to one side of the "=": x^2 +2x-9 = 0 Factor, aka break the equation down to the simplest form: (x-3)(x-3) = 0 Divide by (x-3) to cancel out one of them: x-3=0 Add 3 to both sides to solve for x: x=3