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Julide M.
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Geometry
TutorMe
Question:

Simplify the radicand: $​$\sqrt{25+144}$​$

Julide M.

$$\sqrt{25+144} = \sqrt{169}$$ write as the product of prime factors and simplify: $$\sqrt{13^{2}}$$ = 13

Chemistry
TutorMe
Question:

There is 345 mL of a 1.5 M NaCl solution. Water is boiled until the volume of the solution is 250 mL, what will the molarity of the solution be?

Julide M.

First we will identify the variables present. There are 2 variables for Volume (V) and 1 for Molarity (M) and we must solve for the Molarity (M) of the new solution. Therefore we have: V1 = 345 mL M1 = 1.5 M V2 = 250 mL M2 = ? Based on this, we can identify that we must use the dilution equation: M1V1 = M2V2 Plug the information in: (1.5 M)(345 mL) = M2(250 mL) M2 = 2.07 M Therefore, the new solution has a molarity of 2.07 M.

Algebra
TutorMe
Question:

Evaluate 2xy + x for x=2 and y=4

Julide M.

Substitute x for 2 and y for 4 in the given expression 2(2)(4) + (4) = Solve =20

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