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Julide M.
Private Tutor for 5 Years
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Geometry
TutorMe
Question:

Simplify the radicand: $​$\sqrt{25+144}$​$

Julide M.
Answer:

$$\sqrt{25+144} = \sqrt{169}$$ write as the product of prime factors and simplify: $$\sqrt{13^{2}}$$ = 13

Chemistry
TutorMe
Question:

There is 345 mL of a 1.5 M NaCl solution. Water is boiled until the volume of the solution is 250 mL, what will the molarity of the solution be?

Julide M.
Answer:

First we will identify the variables present. There are 2 variables for Volume (V) and 1 for Molarity (M) and we must solve for the Molarity (M) of the new solution. Therefore we have: V1 = 345 mL M1 = 1.5 M V2 = 250 mL M2 = ? Based on this, we can identify that we must use the dilution equation: M1V1 = M2V2 Plug the information in: (1.5 M)(345 mL) = M2(250 mL) M2 = 2.07 M Therefore, the new solution has a molarity of 2.07 M.

Algebra
TutorMe
Question:

Evaluate 2xy + x for x=2 and y=4

Julide M.
Answer:

Substitute x for 2 and y for 4 in the given expression 2(2)(4) + (4) = Solve =20

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