What is the Range of a projectile launched at an angle theta?
Since a launched projectile has a speed Vo, the x component of this velocity is Vo(cos()). the distance the particle travels in the x axis is x = Vo(cos())t, where t is the time the particle hits the ground. The particle will hit the ground at the end of its trajectory when the y axis is zero, thus y(t) = Vo(sin()) - 1/2(g)(t^2), and y(t) = 0. Thus 1/2(g)(t^2) = Vo(sin()), and t = 2Vo(sin()) / g. Substituting the value of t into the x equation, where X = R, as R is the range of the projectile: R = 2(Vo^2)(cos())(sin())/g, and simplifying, using the identity 2cos()sin() = sin(2()), R = Vo^2(sin(2())/g.
Which Operator cannot be overloaded in C++?
The :: operator as this is the operator that allows a classes' function members to be defined outside of the header file.
Calculate the Consumer and Producer Surplus at equilibrium, and at a price floor of 9$. With ta demand function of Qd = -20X + 500 and a supply function of Qs = 30X - 200.
After creating a graph of the two functions, with price on the Y axis and quantity on the X axis, note the intersection point on the graph. This will be the equilibrium price and quantity. The consumer surplus is all of the area above the equilibrium Y line, and under the demand curve, while the Producer surplus is the are under the equilibrium line and above the supply curve.