The are two masses M1 = 5 grams and M2 = 20 grams. M2 is at rest. M1 approaches M2 at 10 m/s. After the collision they stick together and move with a velocity V. Find V. .
Step 1: P = MV where P is momentum V is velocity and M is mass. Step 2: Because momentum is always conserved total momentum of the system must be equal to the momentum after the collision. Step 3: Before the collision P = M1 * 10 m/s = 5 g * 10m/s = 50 g*(m/s) Step 4: Mass after colision = M1 + M2 = 25 g Step 5: P before = P after = 50 g*(m/s) = V * 25 ----> 50/25 = 2 Solution: V = 2 m/s
Name the 4 types of macro-molecules.
Lipids, Proteins, Carbohydrates, and Nucleic Acids.
Given 3(x^2) - 6x = 2y and 3x+y = 24, find x.
Solution x = 4 or -4 Step 1: Move -6x over so that the first equation now reads 3(x^2) = 6x + 2y Step 2: By recognizing that 6x + 2y is double 3x+y, 2*(24) can be substituted for 6x + 2y leaving the equation 3(x^2) = 48 Step 3: Divide both side by 3 to get x^2 = 16 Step 4: The square root of 14 is + or - 4