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# Tutor profile: Chloe C.

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Chloe C.
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## Questions

### Subject:Basic Math

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Question:

Which fraction is bigger? (9/12)=(6/8)

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Chloe C.

1. To figure out which fraction is bigger, we must simplify each fraction to have a common denominator. In this case, both denominators, 12 and 8, have a factor of 4. 2. Next, We must divide the numerator and denominator of the fraction (9/12) by 3 to get the common denominator 4, resulting in the simplified fraction (3/4). 3. Now, we must divide the fraction (6/8) by 2 to get the common denominator 4, resulting in the simplified fraction (3/4). 4. In this case, the fractions are of equal value.

### Subject:Psychology

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Question:

What is the difference between positive and negative reinforcement?

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Chloe C.

Positive and negative reinforcement is not a difference of "good" or "bad" behavior, it is the difference of something being added or subtracted to increase the likelihood of behavior. Positive reinforcement is defined as something being added to increase the likelihood of a behavior. For example, in elementary school, kids get gold stars next to their name for behaving well in class. The gold star is the thing being added to increase the likelihood of the kids behaving well in class. Negative reinforcement, on the other hand, is defined as something being removed to increase the likelihood of a behavior. For instance, when one gets into their car, a beeping sound goes off until one puts on their seatbelt. The beeping sound is being removed after one puts on their seatbelt, thus increasing the likelihood of one putting on their seatbelt so they do not have to hear the beeping sound.

### Subject:Algebra

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Question:

Find the value of x: 5x+2(x+7)=14x-7

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Chloe C.

To find the value of x, we must have the approach of getting x to one side of the equation. We will be guided by using PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction). 1. The first step is evaluating the parentheses (P in PEMDAS) with the attached constant: 2(x+7). Here, we must distribute (multiply, M in PEMDAS) the 2 to the variable, x, and the constant, 7, inside the parentheses, becoming 2x+14. Now, we rewrite the equation: 5x+2x+14=14x-7. 2. The next step is adding (A in PEMDAS) like terms on either side of the equation, in this case 5x+2x=7x. We rewrite the equation once more with the added like terms: 7x+14=14x-7. 3. We still have the goal of getting x to one side of the equation, so the next step is subtracting (S in PEMDAS) 7x from 14x (two like terms); the rewritten equation will be 14=(14x-7x)-7. After the subtraction 14x-7x=7x is complete, the equation will be 14=7x-7. 4. Now, we add (A in PEMDAS) 7 to 14 (two like terms): the rewritten equation is (14+7)=7x, and after the addition is complete, the rewritten equation is 21=7x. 5. The final step is dividing (D in PEMDAS) 7 from 21 to bring x alone on one side of the equation, leaving the rewritten equation to be (21/7)=x. 6. After the division is complete, we get the answer x=3.

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