Niki Lee M.

Biomedical Science Student attending Texas A&M and hoping to help others :)

Tutor Satisfaction Guarantee

Geometry

TutorMe

Question:

Given a parralelogram starting in the top left corner with point A and going clockwise to B, C, and D, the side AD and BC are the shorter sides with a length of 3.3 inches. The width of the parallelogram is 7.4 inches. Angle A is 121.5 degrees and Angle D is 58.5 degrees. What is the Area of the parallelogram?

Niki Lee M.

Answer:

To find the area of a parallelogram, you must know that the equation is A = width x height. To find height, you must use sin, cos, tan to find h. Since we are given the length of the hypotenuse (3.3 in) and angle of 58.5 degrees, we can use sine to find the opposite side (the height). Sin58.5 = opposite/ 3.3 The height (opposite) is 2.81 inches. To find the area we multiply the height of 2.81 inches by the width of 7.4 inches to get 20.8 square inches.

Calculus

TutorMe

Question:

$$\lim _{x\to \infty \:}\left(\frac{x^5-4x^3}{2x^4}\right)=\infty $$

Niki Lee M.

Answer:

1. Separate equation and factor out 1/2 $$x^5/2x^4-4x^3/2x^4$$ = 1/2 $$(x^5/x^4-4x^3/x^4)$$ 2. Combine again and write 1/2 outside of limit 1/2 $$\lim _{x\to \infty \:\:}$$ $$(x^5-4x^3)/(x^4)$$ 3. Simplify by removing $$x^3$$ from the denominator $$x^5/x^3$$ = $$x^2$$ and $$-4x^3/x^3$$ = -4 4. So far we have, $$(x^2-4)/x$$ When it is just a subtraction left, we can separate the equation and find the limit of each part $$\frac{1}{2}\left(\lim _{x\to \infty \:}\left(x\right)-\lim _{x\to \infty \:}\left(\frac{4}{x}\right)\right)$$ 5. Simplify to get 1/2 ($$ \infty \:$$ - 0) 6. ^ 1/2 of $$\infty \:$$ is $$\infty \:$$ and 1/2 of zero is zero so the answer is $$\infty \:$$

Algebra

TutorMe

Question:

Simplify: $$((4x^7y^3)/(3xy^4)) (5x^2/y)$$

Niki Lee M.

Answer:

Part 1) Simplify the part in which can be simplified $$(4x^7y^3)/(3xy^4)$$ = ($$4x^6/3y) $$ Part 2) Multiply the top half $$(4x^6) (5x^2) $$=$$20x^8$$ Part 3) Multiply the bottom half (3y) (y) = $$3y^2$$ Part 4) combine part 2 and 3 $$20x^8/3y^2$$

Send a message explaining your

needs and Niki Lee will reply soon.

needs and Niki Lee will reply soon.

Contact Niki Lee

Ready now? Request a lesson.

Start Session

FAQs

What is a lesson?

A lesson is virtual lesson space on our platform where you and a tutor can communicate.
You'll have the option to communicate using video/audio as well as text chat.
You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.

How do I begin a lesson?

If the tutor is currently online, you can click the "Start Session" button above.
If they are offline, you can always send them a message to schedule a lesson.

Who are TutorMe tutors?

Many of our tutors are current college students or recent graduates of top-tier universities
like MIT, Harvard and USC.
TutorMe has thousands of top-quality tutors available to work with you.