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Tutor profile: Julia M.

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Julia M.
Bachelors in Genetics, Published Author, & Current Applicant to Medical School
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Questions

Subject: MCAT

TutorMe
Question:

Which of the following would make the best PCR primer?

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Julia M.
Answer:

A. 5' AATCGATTC 3' B. 5' CAAATCAAG 3' C. 5' AATTATACA 3' D. 5' CGCTACGCG 3' The correct answer is D because the ideal PCR primer has multiple cytosines (C's) and guanines (G's) at the 5 and 3 prime ends, because C & G form 3 hydrogen bonds, and are therefore more strongly bonded than adenine (A) & thymidine (T), which only form 2 hydrogen bonds.

Subject: Biochemistry

TutorMe
Question:

Denaturing a protein will break which of the following:

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Julia M.
Answer:

A. the covalent bond between the N and C termini of two leucine residues B. the hydrogen bond between two glycine residues in a B-sheet C. the hydrophobic bonds between two aspartic acid residues D. the C-C bond in the deoxyribose backbone of DNA The correct answer is B. Denaturing a protein will disrupt the quaternary, tertiary, and secondary structure. Answer A describes the primary structure, so it is incorrect. Answer B describes the secondary structure, so it is correct. Answer C is incorrect because aspartic acid residues would not be expected to form hydrophobic bonds because aspartic acid is a polar & acidic amino acid. Answer D is incorrect because denaturing DNA would not disrupt the backbone, however, it would disrupt hydrogen bonds between complementary base-pairs.

Subject: Biology

TutorMe
Question:

A particular genome is composed of 29% guanine. What percentage of the genome is adenine?

Inactive
Julia M.
Answer:

A. 29% B. 21% D. 16% E. 19% The correct answer is B. In order to answer this question, it is easiest to think % CG + % AT = 100 % of the genome since C & G complementary base pair, and A & T complementary base pair. So the best first step is to double the % C because C & G hydrogen bond in the DNA double helix, when you do so, you get 58%. Next, you take 100 - % CG = % AT, so you take 100 % of the total genome - 58 (the % c + g) = % of A & T in genome, after doing this math you get 42%. Lastly, you divide the 42% by two, because 42 is the total percent of A & T base pairs. Dividing 42 by 2 gives you a total of 21 %.

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