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# Tutor profile: Peter V.

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Peter V.
Maths, Physics and Computer Science Teacher
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## Questions

### Subject:Physics (Newtonian Mechanics)

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Question:

A ball is kicked from the horizontal ground with an initial velocity of 40 m/s at an angle of 28 degrees to the horizontal. Calculate the initial horizontal component Vh as well as the time is taken to reach the maximum height above the ground.

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Peter V.

Horizontal component (Vh) = Vcosx Vh = (40)(cos28) Vh = 35.32 m/s Vertical component = Vsinx = (40)(sin28) = 18.78 m/s Therefore using v = u + at V = 0 (at the max height) U = 18.78 (initial vertical velocity) a = -9.81 (deceleration due to gravity) t = unknown variable 0 = 18.78 + (-9.81)t 9.81t = 18.78 t = 1.91s to reach the maximum height

### Subject:Algebra

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Question:

The length of a rectangular field is 7/5 its width. If the perimeter of the field is 450 meters, what are the length and width of the field?

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Peter V.

Let length = x Let width = y x = 7/5y Perimeter = 2x + 2y BUT x = 7/5y So P = 2(7/5y) + 2y 450 = 14/5y + 10/5y 450 = 24/5y y = 93.75m (width) Therefore x = 7/5(93.75) = 131.25m (length)

### Subject:Physics

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Question:

A uniform beam PQ is balanced on a pivot. The length of the beam is 3.0m and its weight is 50N. The beam is supported on a pivot 1.0m from end P. A load of weight W is hung from end P and the beam is in equilibrium. What is the value of W?

Inactive
Peter V.

For equilibrium, all clockwise moments must equal all anti-clockwise moments. Moment = Force x perpendicular distance from pivot Clockwise moments = Weight of bar x 0.5m (halfway) Therefore = 50 x 0.5 Anti clockwise moments = W x 1 Therefore: 50 x 0.5 = W x 1 W = 25N The weight hung from end P is 25N

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