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Danielle J.

Tutor for 4 years, Comp Science major at NYU

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Writing

TutorMe

Question:

Honestly. Just read my college essays.

Danielle J.

Answer:

https://docs.google.com/document/d/1-1hkTattxvBDfxmwN0lxk-qFVpcf6EsUjqeuzy_XvUY/edit?usp=sharing

Calculus

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Question:

Evaluare the following function at each of the function evaluations. f(x) = 7 - 5x - 2x^2 1.)f(0) 2)f(6-q)

Danielle J.

Answer:

To evaluate the function at each of the function evaluations. We simply plug the values in. #1 is simple. We simply plug 0 in everywhere that we see an x. SO. 5 * 0 = 0 AND 2(0)^2 = 0 . THEN 7 - 0 = 7 so f(0) = 7 2. This ones a little tricker. We're plugging in a whole expression in for x. So everywhere there is an x. we're going to replace it with (6-q) 7 - 5(6-q) - 2(6-q)^2 We then multiple the parentheses out. Taking account of the order of operations and signs 7 - 30 + 5q(two negatives multiplied makes a positive) For the next part PEMDAS. States we take care of the exponent first. so. (6-q) * (6-q) = 36 - 6q -6q +q^2(two negatives! again!) the two 6qs cancel. Leaving us with 36 + q^2. We then add this to our other result. 7 - 30 + 5q + 36 +q^2 . We add the integers. Leaving us with 13 + 5q + q^2

Algebra

TutorMe

Question:

Add 12x^2 + 7x^3 to 4x^4 - 2x^2

Danielle J.

Answer:

The only variables(x) that we can add, are the ones with similar exponents. So we can see that 12x and 2x are both raised to the power of 2. We are adding the expressions, but adding a negative does not change its sign. So 12x^2 - 2x^2 = 10x^2 . We can see that none of the other variables are raised to the same power, therefore we can simply add them all together. Our final expression is 10x^2 + 7x^3 + 4x^4

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