TutorMe homepage
Subjects
PRICING
COURSES
SIGN IN
Start Free Trial
Danielle J.
Tutor for 4 years, Comp Science major at NYU
Tutor Satisfaction Guarantee
Writing
TutorMe
Question:

Honestly. Just read my college essays.

Danielle J.
Answer:

https://docs.google.com/document/d/1-1hkTattxvBDfxmwN0lxk-qFVpcf6EsUjqeuzy_XvUY/edit?usp=sharing

Calculus
TutorMe
Question:

Evaluare the following function at each of the function evaluations. f(x) = 7 - 5x - 2x^2 1.)f(0) 2)f(6-q)

Danielle J.
Answer:

To evaluate the function at each of the function evaluations. We simply plug the values in. #1 is simple. We simply plug 0 in everywhere that we see an x. SO. 5 * 0 = 0 AND 2(0)^2 = 0 . THEN 7 - 0 = 7 so f(0) = 7 2. This ones a little tricker. We're plugging in a whole expression in for x. So everywhere there is an x. we're going to replace it with (6-q) 7 - 5(6-q) - 2(6-q)^2 We then multiple the parentheses out. Taking account of the order of operations and signs 7 - 30 + 5q(two negatives multiplied makes a positive) For the next part PEMDAS. States we take care of the exponent first. so. (6-q) * (6-q) = 36 - 6q -6q +q^2(two negatives! again!) the two 6qs cancel. Leaving us with 36 + q^2. We then add this to our other result. 7 - 30 + 5q + 36 +q^2 . We add the integers. Leaving us with 13 + 5q + q^2

Algebra
TutorMe
Question:

Add 12x^2 + 7x^3 to 4x^4 - 2x^2

Danielle J.
Answer:

The only variables(x) that we can add, are the ones with similar exponents. So we can see that 12x and 2x are both raised to the power of 2. We are adding the expressions, but adding a negative does not change its sign. So 12x^2 - 2x^2 = 10x^2 . We can see that none of the other variables are raised to the same power, therefore we can simply add them all together. Our final expression is 10x^2 + 7x^3 + 4x^4

Send a message explaining your
needs and Danielle will reply soon.
Contact Danielle
Ready now? Request a lesson.
Start Session
FAQs
What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Session" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.