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Kassidy O.

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Physics

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Question:

A car traveling at 15 m/s undergoes an acceleration of 3 m/s^2 for 10 seconds. How far did it travel when it was accelerating?

Kassidy O.

Answer:

the distance = v(initial)*t + (1/2)*(a*t^2) so v(initial) = 15m/s t = 10 a = 3 so, 15*10 + (1/2)*(3)*(10)^2 = 300 m

Algebra

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Question:

what is 81^(3/2)

Kassidy O.

Answer:

729

Algebra

TutorMe

Question:

g(x) = 2x+3 f(x) = 10x^2 + x - 8 What does f(g(x)) = ?

Kassidy O.

Answer:

f(g(x)) = f(2x +3) = 10(2x+3)^2 + 2x + 3 - 8 = 10(4x^2 + 12x + 9) + 2x - 5 40x^2 + 120x + 90 + 2x -5 40x^2 + 122x + 85 thus, by the quadratic formula, x = -1.07 and 1.97

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