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Ashwin S.
Ph.D Candidate in Chemical Engineering
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Pre-Calculus
TutorMe
Question:

dy/dx = 2y/x. Integrate

Ashwin S.
Answer:

dy/dx = 2y/x dy/2y =1/x dx 1/2 lny =lnx

Basic Math
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Question:

Solve x^2+2x+1=0

Ashwin S.
Answer:

(x+1)^2=0 x=-1

Chemical Engineering
TutorMe
Question:

How do you design a heat exchanger?

Ashwin S.
Answer:

Determine the temperature change required. Determine the area of heat transfer Determine the energy transferred through the area Find out the overall heat transfer coefficient Iterate the area till the conditions are met

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